Aldehydes, Ketones and Carboxylic Acids
353 Questions
2022
JEE Mains
Numerical
JEE Main 2022 (Online) 29th July Evening Shift
The number of stereoisomers formed in a reaction of $(±)\mathrm{Ph}(\mathrm{C}=\mathrm{O}) \mathrm{C}(\mathrm{OH})(\mathrm{CN}) \mathrm{Ph}$ with $\mathrm{HCN}$ is ___________.
$\left[\right.$where $\mathrm{Ph}$ is $-\mathrm{C}_{6} \mathrm{H}_{5}$]
Correct Answer: 3
Explanation:
Number of stereoisomers = 3
2022
JEE Mains
Numerical
JEE Main 2022 (Online) 27th July Evening Shift
The spin only magnetic moment of the complex present in Fehling's reagent is __________ B.M. (Nearest integer).
Correct Answer: 2
Explanation:
In the complex present in Fehling's reagent, $\mathrm{Cu}^{+2}$ ion is present.
So, spin only magnetic moment
$ =\sqrt{1(1+2)} $
$ \begin{aligned} & =\sqrt{3} \simeq 2 \mathrm{~B} . \mathrm{M} \end{aligned} $
So, spin only magnetic moment
$ =\sqrt{1(1+2)} $
$ \begin{aligned} & =\sqrt{3} \simeq 2 \mathrm{~B} . \mathrm{M} \end{aligned} $
2022
JEE Mains
Numerical
JEE Main 2022 (Online) 25th July Morning Shift
In the given reaction
The number of chiral carbon/s in product A is ___________.
Correct Answer: 2
Explanation:
2 chiral carbons are there in product A.
2022
JEE Mains
Numerical
JEE Main 2022 (Online) 30th June Morning Shift
A hydrocarbon 'X' is found to have molar mass of 80. A 10.0 mg of compound 'X' on hydrogenation consumed 8.40 mL of H2 gas (measured at STP). Ozonolysis of compound 'X' yields only formaldehyde and dialdehyde. The total number of fragments/molecules produced from the ozonolysis of compound 'X' is _____________.
Correct Answer: 4
Explanation:
Moles of $\mathrm{X}=\frac{10 \mathrm{mg}}{80}=0.125 \mathrm{~m} \mathrm{~mol}$.
moles consumed of $\mathrm{H}_{2}=\frac{8.4}{22.4} 0.375 \mathrm{~m} \mathrm{~mol}$.
$\frac{\mathrm{n}_{\mathrm{H}_{2}}}{\mathrm{n}_{\mathrm{X}}}=\frac{0.375}{0.125}=3$
So, the compound $\mathrm{X}$ have 3 double bond.
Ozonolysis of the compound yield formaldehyde and dialdehyde.
The compound is
$ \mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2} $
Molecular mass $=(12 \times 6)+1 \times 8=72+8=80 \,\mathrm{amu}$
Ozonolysis form:
moles consumed of $\mathrm{H}_{2}=\frac{8.4}{22.4} 0.375 \mathrm{~m} \mathrm{~mol}$.
$\frac{\mathrm{n}_{\mathrm{H}_{2}}}{\mathrm{n}_{\mathrm{X}}}=\frac{0.375}{0.125}=3$
So, the compound $\mathrm{X}$ have 3 double bond.
Ozonolysis of the compound yield formaldehyde and dialdehyde.
The compound is
$ \mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2} $
Molecular mass $=(12 \times 6)+1 \times 8=72+8=80 \,\mathrm{amu}$
Ozonolysis form:
2022
JEE Mains
Numerical
JEE Main 2022 (Online) 29th June Evening Shift
In the given reaction,
The number of $\pi$ electrons present in the product 'P' is _________.
Correct Answer: 4
Explanation:
2022
JEE Advanced
MSQ
JEE Advanced 2022 Paper 1 Online
Considering the reaction sequence given below, the correct statement(s) is(are)
A.
$\mathbf{P}$ can be reduced to a primary alcohol using $\mathrm{NaBH}_{4}$.
B.
Treating $\mathbf{P}$ with conc. $\mathrm{NH}_{4} \mathrm{OH}$ solution followed by acidification gives $\mathbf{Q}$.
C.
Treating $\mathbf{Q}$ with a solution of $\mathrm{NaNO}_{2}$ in aq. $\mathrm{HCl}$ liberates $\mathrm{N}_{2}$.
D.
$\mathbf{P}$ is more acidic than $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}$.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 1st September Evening Shift
Experimentally reducing a functional group cannot be done by which one of the following reagents?
A.
Pt-C/H2
B.
Na/H2
C.
Pd-C/H2
D.
Zn/H2O
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 1st September Evening Shift
In the following sequence of reactions a compound A, (molecular formula C6H12O2) with a straight chain structure gives a C4 carboxylic acid. A is :
A.
$C{H_3} - C{H_2} - COO - C{H_2} - C{H_2} - C{H_3}$
B.
C.
$C{H_3} - C{H_2} - C{H_2} - COO - C{H_2} - C{H_3}$
D.
$C{H_3} - C{H_2} - C{H_2} - O - CH = CH - C{H_2} - OH$
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 1st September Evening Shift
Given below are two statements :
Statement I : The nucleophilic addition of sodium hydrogen sulphite to an aldehyde or a ketone involves proton transfer to form a stable ion.
Statement II : The nucleophilic addition of hydrogen cyanide to an aldehyde or a ketone yields amine as final product.
In the light of the above statements, choose the most appropriate answer from the options given below :
Statement I : The nucleophilic addition of sodium hydrogen sulphite to an aldehyde or a ketone involves proton transfer to form a stable ion.
Statement II : The nucleophilic addition of hydrogen cyanide to an aldehyde or a ketone yields amine as final product.
In the light of the above statements, choose the most appropriate answer from the options given below :
A.
Both Statement I and Statement are true.
B.
Statement I is true but Statement II is false.
C.
Statement I is false but Statement II is true.
D.
Both Statement I and Statement II are false.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 31st August Evening Shift
The structures A and B formed in the following reaction are : [Ph = $-$C6H5]
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 31st August Evening Shift
For the reaction given below :-
The compound which is not formed as a product in the reaction is a :
The compound which is not formed as a product in the reaction is a :
A.
compound with both alcohol and acid functional groups
B.
monocarboxylic acid
C.
dicarboxylic acid
D.
diol
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 31st August Morning Shift
The structure of product C, formed by the following sequence of reactions is :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 27th August Evening Shift
Given below are two statements :
Statement I : Ethyl pent-4-yn-oate on reaction with CH3MgBr gives a 3$^\circ$-alcohol.
Statement II : In this reaction one mole of ethyl pent-4-yn-oate utilizes two moles of CH3MgBr.
In the light of the above statements, choose the most appropriate answer from the options given below :
Statement I : Ethyl pent-4-yn-oate on reaction with CH3MgBr gives a 3$^\circ$-alcohol.
Statement II : In this reaction one mole of ethyl pent-4-yn-oate utilizes two moles of CH3MgBr.
In the light of the above statements, choose the most appropriate answer from the options given below :
A.
Both Statement I and Statement II are false.
B.
Statement I is false but Statement II is true.
C.
Statement I is true but Statement II is false.
D.
Both Statement I and Statement II are true.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 27th August Evening Shift
Which one of the following reactions will not yield propionic acid?
A.
CH3CH2COCH3 + OI$-$/H3O+
B.
CH3CH2CH3 + KMnO4(Heat), OH$-$/H3O+
C.
CH3CH2CCl3 + OH$-$/H3O+
D.
CH3CH2CH2Br + Mg, CO2 dry ether/H3O+
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 27th August Morning Shift
The structure of the starting compound P used in the reaction given below is :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 26th August Morning Shift
The major products formed in the following reaction sequence A and B are :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 26th August Morning Shift
The correct sequential addition of reagents in the preparation of 3-nitrobenzoic acid from benzene is :
A.
Br2/AlBr3, HNO3/H2SO4, Mg/ether, CO2, H3O+
B.
Br2/AlBr3, NaCN, H3O+, HNO3/H2SO4
C.
Br2/AlBr3, HNO3/H2SO4, NaCN, H3O+
D.
HNO3/H2SO4, Br2/AlBr3, Mg/ether, CO2, H3O+
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 27th July Morning Shift
Which one of the following compounds will give orange precipitate when treated with 2, 4-dinitrophenyl hydrazine?
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 25th July Evening Shift
Maleic anhydride can prepared by :
A.
Heating trans-but-2-enedioic acid
B.
Heating cis-but-2-enedioic acid
C.
Treating cis-but-2-enedioic acid with alcohol and acid
D.
Treating trans-but-2-enedioic acid with alcohol and acid
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 25th July Evening Shift
[where $Et \Rightarrow - {C_2}{H_5}{}^tBu \Rightarrow {(C{H_3})_3}C - $]
Consider the above reaction sequence, Product "A" and Product "B" formed respectively are :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 25th July Morning Shift
Consider the given reaction, the product 'X' is :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 25th July Morning Shift
Which one of the following compounds will liberate CO2, when treated with NaHCO3 ?
A.
${(C{H_3})_3}\mathop {NH}\limits^ \oplus \mathop {Cl}\limits^\Theta $
B.
${(C{H_3})_4}\mathop N\limits^ \oplus \mathop O\limits^\Theta H$
C.
D.
$C{H_3}N{H_2}$
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 20th July Evening Shift
The major product (P) in the following reaction is :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 20th July Evening Shift
The correct order of their reactivity towards hydrolysis at room temperature is :
A.
(A) > (B) > (C) > (D)
B.
(D) > (A) > (B) > (C)
C.
(D) > (B) > (A) > (C)
D.
(A) > (C) > (B) > (D)
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 20th July Morning Shift
Which among the above compound/s does/do not form Silver mirror when treated with Tollen's reagent?
A.
(I), (III) and (IV) only
B.
Only (IV)
C.
Only (II)
D.
(III) and (IV) only
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 18th March Evening Shift
Consider the above reaction, the product 'X' and 'Y' respectively are :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 18th March Morning Shift
Consider the above chemical reaction and identify product "A"
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 18th March Morning Shift
Considering the above chemical reaction, identify the product "X" :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 17th March Morning Shift
The product ''A'' in the above reaction is :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 17th March Morning Shift
Mesityl oxide is a common name of :
A.
3-Methyl cyclohexane carbaldehyde
B.
4-Methyl pent-3-en-2-one
C.
2,4-Dimethyl pentan-3-one
D.
2-Methyl cyclohexanone
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 16th March Evening Shift
In the above reaction, the reagent ''A'' is :
A.
LiAlH4
B.
NaBH4, H3O+
C.
HCl, Zn $-$ Hg
D.
Alkaline KMnO4, H+
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 16th March Morning Shift
The product ''P'' in the above reaction is :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 16th March Morning Shift
Assertion A : Enol form of acetone [CH3COCH3] exists in < 0.1% quantity. However, the enol form of acetyl acetone [CH3COCH2OCCH3] exists in approximately 15% quantity.
Reason R : Enol form of acetyl acetone is stabilized by intramolecular hydrogen bonding, which is not possible in enol form of acetone.
Choose the correct statement :
Reason R : Enol form of acetyl acetone is stabilized by intramolecular hydrogen bonding, which is not possible in enol form of acetone.
Choose the correct statement :
A.
Both A and R are true but R is not the correct explanation of A
B.
A is true but R is false
C.
A is false but R is true
D.
Both A and R are true and R is the correct explanation of A
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 26th February Evening Shift
Identify A in the following chemical reaction.
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 26th February Evening Shift
2, 4-DNP test can be used to identify :
A.
ether
B.
amine
C.
aldehyde
D.
halogens
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 26th February Evening Shift
Considering the above reaction, the major product among the following is :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 26th February Evening Shift
Identify A in the given chemical reaction.
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 25th February Evening Shift
The major product of the following reaction is :
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 25th February Morning Shift
Which one of the following reactions will not form acetaldehyde?
A.
$C{H_3}C{H_2}OH\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{573K}^{Cu}} $
B.
$C{H_3}C{H_2}OH\buildrel {Cr{O_3} - {H_2}S{O_4}} \over
\longrightarrow $
C.
$C{H_2} = C{H_2} + {O_2}\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{{H_2}O}^{Pd(II)/Cu(II)}} $
D.
$C{H_3}CN\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{ii)\,{H_2}O}^{i)\,DIBAL - H}} $
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 25th February Morning Shift
Compound(s) which will liberate carbon dioxide with sodium bicarbonate solution is/are :
A.
C only
B.
B only
C.
B and C only
D.
A and B only
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 25th February Morning Shift
The major product of the following chemical reaction is :
A.
$C{H_3}C{H_2}CHO$
B.
$C{H_3}C{H_2}C{H_3}$
C.
$C{H_3}C{H_2}C{H_2}OH$
D.
${(C{H_3}C{H_2}CO)_2}O$
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 24th February Evening Shift
Which one of the following carbonyl compounds cannot be prepared by addition of water on an alkyne in the presence of HgSO4 and H2SO4?
A.
B.
C.
D.
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 24th February Evening Shift
Which of the following reagent is suitable for the preparation of the product in the above reaction?
A.
Red P + Cl2
B.
$N{H_2} - N{H_2}/{C_2}{H_5}\mathop O\limits^\Theta \mathop N\limits^ \oplus a$
C.
NaBH4
D.
Ni/H2
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 24th February Evening Shift
Match List - I and List - II.
Choose the correct answer from the options given below :
| List-I | List-II | ||
|---|---|---|---|
| (a) |  |
(i) | $\mathrm{Br}_{2} / \mathrm{NaOH}$ |
| (b) |  |
(ii) | $\mathrm{H}_{2} / \mathrm{Pd}-\mathrm{BaSO}_{4}$ |
| (c) |  |
(iii) | $\mathrm{Zn}(\mathrm{Hg}) / \mathrm{H}$ Conc. $\mathrm{HCl}$ |
| (d) |  |
(iv) | $\mathrm{Cl}_{2}$ Red $\mathrm{P}, \mathrm{H}_{2} \mathrm{O}$ |
Choose the correct answer from the options given below :
A.
(a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
B.
(a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
C.
(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
D.
(a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
2021
JEE Mains
MCQ
JEE Main 2021 (Online) 24th February Morning Shift
Which of the following reagent is used for the following reaction ?
$ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_3 \stackrel{?}{\longrightarrow} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHO} $
$ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_3 \stackrel{?}{\longrightarrow} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHO} $
A.
Molybdenum oxide
B.
Manganese acetate
C.
Copper at high temperature and pressure
D.
Potassium permanganate
2021
JEE Mains
Numerical
JEE Main 2021 (Online) 18th March Evening Shift
In Tollen's test for aldehyde, the overall number of electron(s) transferred to the Tollen's reagent formula [Ag(NH3)2]+ per aldehyde group to form silver mirror is ___________. (Round off to the Nearest Integer).
Correct Answer: 2
Explanation:
Total 2e- transfer to Tollen's reagent.
2021
JEE Mains
Numerical
JEE Main 2021 (Online) 18th March Evening Shift
Consider the above reaction where 6.1 g of Benzoic acid is used to get 7.8 g of m-bromo benzoic acid. The percentage yield of the product is __________
(Round off to the Nearest Integer).
[Given : Atomic masses : C : 12.0 u, H : 1.0 u, O : 16.0 u, Br : 80.0 u]
Correct Answer: 78
Explanation:
Moles of Benzoic acid = ${{6.1} \over {122}}$ = moles of m-bromobenzoic acid
So, weight of m-bromobenzoic acid = ${{6.1} \over {122}}$ $\times$ 201 gm
= 10.05 gm
% yield = ${{Actual\,weight} \over {Theoretical\,weight}} \times 100$
$ = {{7.8} \over {10.05}} \times 100$ = 77.61%
So, weight of m-bromobenzoic acid = ${{6.1} \over {122}}$ $\times$ 201 gm
= 10.05 gm
% yield = ${{Actual\,weight} \over {Theoretical\,weight}} \times 100$
$ = {{7.8} \over {10.05}} \times 100$ = 77.61%
2021
JEE Mains
Numerical
JEE Main 2021 (Online) 17th March Evening Shift
The total number of C-C sigma bond/s in mesityl oxide (C6H10O) is __________. (Round off to the Nearest Integer).
Correct Answer: 5
Explanation:
Structure of mesityl oxide is
Number of C–C sigma bonds = 5
Number of C–C sigma bonds = 5
2021
JEE Mains
Numerical
JEE Main 2021 (Online) 25th February Evening Shift
The number of compound/s given below which contain/s -COOH group is __________. (Integer answer)
(A) Sulphanilic acid
(B) Picric acid
(C) Aspirin
(D) Ascorbic acid
(A) Sulphanilic acid
(B) Picric acid
(C) Aspirin
(D) Ascorbic acid
Correct Answer: 1
Explanation:
The structures of the given compounds are
(A) Sulphanilic acid
(B) Picric acid
(C) Aspirin
(D) Ascorbic Acid
$ \therefore $ Only 1 compound has –COOH group
(A) Sulphanilic acid
(B) Picric acid
(C) Aspirin
(D) Ascorbic Acid
$ \therefore $ Only 1 compound has –COOH group
2021
JEE Advanced
Numerical
JEE Advanced 2021 Paper 1 Online
In the reaction given below, the total number of atoms having sp2 hybridization in the major product P is _________.
Correct Answer: 8OR12
Explanation:
Alkene on treatment with ozone (O3) followed by
treatment with Zn/H2O gives carbonyl compounds.
Carbonyl compounds react with NH2OH to give oximes.
There are four sp2-carbon atoms, four sp2-nitrogen atoms and four sp2-oxygen atoms as shown in structures I and II.
Therefore, total number of atoms having sp2-hybridisation are twelve (12).