Hydrocarbons
Hydrolysis of an alkyl bromide $\left(\mathrm{C}_5 \mathrm{H}_{11} \mathrm{Br}\right)$ follows first order kinetics. Reaction of $X$ with Mg in dry ether followed by treatment of $\mathrm{D}_2 \mathrm{O}$ gave $Y$, What is $Y$ ?
An alkene $X\left(\mathrm{C}_4 \mathrm{H}_8\right)$ on reaction with HBr gave $Y\left(\mathrm{C}_4 \mathrm{H}_9 \mathrm{Br}\right)$. Reaction of $Y$ with benzene in the presence of anhydrous $\mathrm{AlCl}_3$ gave Z which is resistant to oxidation with $\mathrm{KMnO}_4-\mathrm{KOH}$. What are $X, Y, Z$ respectively?
An alkene $X\left(\mathrm{C}_4 \mathrm{H}_8\right)$ does not exhibit cis-trans is memerisn Reaction of $X$ with $\mathrm{Br}_2$ in the presence of UV light gane $Y$. What is $Y$ ?
$
\text { Here, c-3 of } X \text { is the allyl carbon }\left(2^{\circ}\right) \text {. }
$
What are $X$ and $Y$ respectively in the following reaction sequence?
$ \text { Isopentane } \xrightarrow{\mathrm{KMnO}_4} X \xrightarrow{\text { Dehydration }} Y \text { Major } $
In the above reaction, left hand side and right hand side rings are named as '$\mathrm{A}$' and 'B' respectively. They undergo ring expansion. The correct statement for this process is:
The major product formed in the following reaction is
Choose the correct answer from the options given below :
Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R.
In the light of the above statements, choose the correct answer from the options given below:
Find out the major product from the following reaction.
In the following reaction, 'B' is
'$\mathrm{X}$' is :
But-2-yne is reacted separately with one mole of Hydrogen as shown below :
A. A is more soluble than B.
B. The boiling point & melting point of A are higher and lower than B respectively.
C. A is more polar than B because dipole moment of A is zero.
D. $\mathrm{Br_2}$ adds easily to B than A.
Identify the incorrect statements from the options given below :
Choose the correct set of reagents for the following conversion.
trans $\left(\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\right) \rightarrow \operatorname{cis}\left(\mathrm{Ph}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\right)$
The major products 'A' and 'B', respectively, are
The one giving maximum number of isomeric alkenes on dehydrohalogenation reaction is (excluding rearrangement)
The correct sequence of reagents for the preparation of Q and R is :
Find out the major products from the following reactions.
In the following given reaction, 'A' is
For the given reaction
The total number of possible products formed by tertiary carbocation of A is ____________.
Explanation:
Total 4 products are possible through 3° carbocation
The number of possible isomeric products formed when 3-chloro-1-butene reacts with $\mathrm{HCl}$ through carbocation formation is __________.
Explanation:
Total Possible Isomeric product = 1+3 = 4
Molar mass of the hydrocarbon (X) which on ozonolysis consumes one mole of $\mathrm{O}_{3}$ per mole of $(\mathrm{X})$ and gives one mole each of ethanal and propanone is _________ $\mathrm{g}~ \mathrm{mol}^{-1}$
(Molar mass of $\mathrm{C}: 12 \mathrm{~g} \mathrm{~mol}^{-1}, \mathrm{H}: 1 \mathrm{~g} \mathrm{~mol}^{-1}$ )
Explanation:
Hydrocarbon $(\mathrm{X})$ is 2-methyl-but-2-ene $\left(\mathrm{C}_5 \mathrm{H}_{10}\right)$
And the molecular mass is $5(12)+10(1)=70$.
Number of bromo derivatives obtained on treating ethane with excess of $\mathrm{Br}_{2}$ in diffused sunlight is ___________
Explanation:
17 mg of a hydrocarbon (M.F. $\mathrm{C_{10}H_{16}}$) takes up 8.40 mL of the H$_2$ gas measured at 0$^\circ$C and 760 mm of Hg. Ozonolysis of the same hydrocarbon yields
The number of double bond/s present in the hydrocarbon is ___________.
Explanation:
Mole of $\mathrm{H}_{2}$ gas
$\Rightarrow 1 \times \frac{8.40}{1000}=\mathrm{n} \times 0.0821 \times 273$
$\Rightarrow \mathrm{n}=3.75 \times 10^{-4}$
Hydrogen molecule used for 1 molecule of hydrocarbon is 3
$=\frac{3.75 \times 10^{-4}}{1.25 \times 10^{-4}}=3$
Maximum number of isomeric monochloro derivatives which can be obtained from 2,2,5,5-tetramethylhexane by chlorination is _____________
Explanation:
Total numbers of isomer = 03
Arrange the following in the correct order of their acidic strength.
I. $\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2$
II. $\mathrm{CH} \equiv \mathrm{CH}$
III. $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$
IV. $\mathrm{CH}_3-\mathrm{CH}_3$
I $<$ II $<$ III $<$ IV
IV $<$ I $<$ III $<$ II
IV $<$ III $<$ II $<$ I
II $<$ III $<$ IV $<$ I
$ \mathrm{C}_3 \mathrm{H}_4+\mathrm{H}_2 \mathrm{O} \xrightarrow[333 \mathrm{~K}]{\mathrm{Hg}^{2+} / \mathrm{H}^{+}}[X] \stackrel{\text { Tautomerisation }}{\rightleftharpoons} Y $
$X$ and $Y$ are respectively
unsaturated alcohol, aldehyde
saturated alcohol, ketone
unsaturated alcohol, ketone
saturated alcohol, aldehyde
Addition of HBr to propene in presence of a peroxide takes place contrary to Markownikoff rule. This can be explained by the mechanism involving
electrophile
free radical
nucleophile
carbene
The rate of attack of an electrophile is least when $X$ in the given compound is
$-\mathrm{NO}_2$
$-\mathrm{CH}_3$
$-OH$
$-\mathrm{NH}_2$
The aromatic compound/species with maximum number of $\pi$-electrons is
phenanthrene
naphthalene
cyclopentadienyl anion
cycloheptatrienyl cation
$ \text { In the conversion of } A \text { to } B \text {, the electrophile involved is } $
$ { }^{\oplus} \mathrm{CH}_3 $
$ \mathrm{Cl}^{\oplus} $
An alkene $X$ on ozonolysis gives a mixture of propan-2-one and methanal. What is $X$ ?
Propene
2-methylpropene
2-methylbut-1-ene
2-methylbut-2-ene
An alkene $X\left(\mathrm{C}_6 \mathrm{H}_{12}\right)$ on ozonolysis gave acetaldehyde and ethyl methyl ketone. What is the product formed when $X$ reacts with HBr ?
An alkene $X$ with formula $\mathrm{C}_4 \mathrm{H}_8$ does not exhibit geometrical isomerism. In the conversion of $X$ to $Y$, the correct sequence of reagents $A$ and $B$ used are ( $Y$ gives iodoform test)
$\mathrm{BH}_3, \mathrm{H}_2 \mathrm{O}_2 / \mathrm{OH}^{-}, \mathrm{PCC}$
$\mathrm{H}_2 \mathrm{O} / \mathrm{H}^{+}, \mathrm{ZnCl}_2 / \mathrm{HCl}$
$\mathrm{H}_2 \mathrm{O} / \mathrm{H}^{+}, \mathrm{Cu} / 573 \mathrm{~K}$
$\mathrm{BH}_3, \mathrm{H}_2 \mathrm{O}_2 / \mathrm{OH}^{-}, \mathrm{Cu} / 573 \mathrm{~K}$
An alkene $(X)$ on ozonolysis gives propanal and ethanal. What is $X$ ?
Pent-2-ene
Pent-1-ene
But-1-ene
But-2-ene
Match the following.
The correct answer is
A-I; B-II; C-III; D-IV
A-II; B-I; C-IV; D-III
A-IV; B-III; C-II; D-I
A-IV; B-II; C-III; D-I
$ \text { Identify ' } Z \text { ' in the following reaction sequence } $
The functional groups in $X$ and $Y$ are respectively.
Thus, the functional group in $X$ and $Y$ are
The major product ( $B$ ) will be formed as per anti-Markownikoff's addition.
Identify product $(Z)$ in the series, of reaction
$\mathrm{CH}_2=\mathrm{CH}_2 \xrightarrow{\mathrm{HBr}} X \xrightarrow{a q . \mathrm{KOH}} Y \xrightarrow[\mathrm{I}_2 \text { excess }]{\mathrm{Na}_2 \mathrm{CO}_3} Z$
Anti-Markownikoff's addition of $\mathrm{HBr}$ is observed in
In acetylene molecule between the carbon atoms there are
$ \stackrel{\bullet}{\mathrm{Cl}}+\mathrm{CH}_{4} \rightarrow \mathrm{A}+\mathrm{B} $
A and B in the above atmospheric reaction step are :
Major product of the following reaction is
A compound ‘$\mathrm{A}$’ on reaction with ‘$\mathrm{X}$’ and ‘$\mathrm{Y}$’ produces the same major product but different by product '$a$' and '$b^{\prime}$. Oxidation of '$a$' gives a substance produced by ants.
'X' and 'Y' respectively are
