The human body does not produce
Vitamin-B$_1$ is
Assertion (A) An optically active amino acid can exist in three forms depending on the pH of the solution.
Reason (R) Amino acids contain both acidic and basic groups, they exist as Zwitter ion in aq. medium, anionic form in acidic medium and cationic form in basic medium.
Identify the product of the following reaction.

During the action of enzyme ‘zymase’ glucose is converted into .............., with the liberation of carbon dioxide gas.

'x', 'y' and 'z' in these reactions are respectively.
(i) Riboflavin (a) Beriberi
(ii) Thiamine (b) Scurvy
(iii) Pyridoxine (c) Cheliosis
(iv) Ascorbic acid (d) Convulsions
Explanation:

Total number of chiral carbon in sucrose = 9
peptide, Ile-Arg-Pro, is _____.
Explanation:
Number of chiral carbons present in the given tripeptide is 4.
Explanation:
No. of chiral centres present in it = 2
groups present in a tripeptide Asp–Glu–Lys is ____.
Explanation:

If the absolute values of the net charge of the peptide at $\mathrm{pH}$ $=2$, $\mathrm{pH}=6$, and $\mathrm{pH}=11$ are $\left|Z_1\right|,\left|Z_2\right|$, and $\left|Z_3\right|$, respectively, then what is $\left|Z_1\right|+\left|Z_2\right|+\left|Z_3\right|$?
Explanation:
There are two $-$NH2 group, and + 1 charge on each group because all amino groups exist in the form of $-$NH$_3^ \oplus $.
Therefore, |Z1| = 2.
At pH = 6,
NH2 of lysine (+ 1) (pH = 9.47) and COOH ($-$1) of glutamic (pH = 3.08) acid, so because of dipolar ion exists, therefore |Z2| = 0.
At pH = 11,
COOH of glutamic acid has ($-$1), COOH of lysine ($-$1) and OH of phenol ($-$1).
Therefore, |Z3| = |$-$3| = 3 (All COOH and OH exist in the form of $-$COO$-$ and $-$O$-$).
$ \therefore $ |Z1| + |Z2| + |Z3| = 2 + 0 + 3 = 5
Xerophthalmia disease is caused by the deficiency of
vitamin K
vitamin $\mathrm{B}_2$
vitamin $\mathrm{B}_6$
vitamin A
- Which of the following statements support the cyclic form for glucose?
(i) It doesn't give Schiff's test.
(ii) It is found to exist in two different crystalline forms.
(iii) It oxidises with nitric acid to give saccharic acid.
(iv) Pentaacetate of glucose doesn't react with hydroxylamine.
(i), (ii) and (iv)
(i), (iii) and (iv)
(ii) and (iii)
(i), (ii) and (iii)
$ \text { Choose the correct Zwitter ionic form for aspartic acid. } $




Amino acids containing heterocyclic ring are
(i) Histidine
(ii) Valine
(iii) Arginine
(iv) Proline
(i), (iv)
(ii), (iii)
(i), (iii)
(ii), (iv)
I. They activate many enzymes
II. They participate in the oxidation of glucose to produce ATP
III. Along with sodium ions they are responsible for the transmission of nerve signals
| Item I | Item II | ||
|---|---|---|---|
| (A) | Ester test | (P) | Tyr |
| (B) | Carbylamine test | (Q) | Asp |
| (C) | Phthalein dye test |
(R) | Ser |
| (S) | Lys | ||


Gly, Asp, Lys, Arg
The correct structure(s) of $\beta $-$L$-glucopyranose is (are) :

Lactose contains $\beta $-glycosidic linkage between C1
of galactose and C4
of glucose.




As, the species bear negatively charge over $\mathrm{COO}^{\ominus}$ and positivity charge over $\mathrm{H}_3 \stackrel{\oplus}{\mathrm{~N}}$-; due to migration of H -atom from -COOH to $-\mathrm{NH}_2$.









