Reason : Hybridization of carbon in diamond and graphite are sp3 and sp2, respectively.
| Column I | Column II |
|---|---|
| (A) Silica gel | (i) Transistor |
| (B) Silicon | (ii) Ion-exchanger |
| (C) Silicone | (iii) Drying agent |
| (D) Silicate | (iv) Sealant |
Reason : The reaction between nitrogen and oxygen requires high temperature.
A group 15 element forms $\mathrm{d} \pi-\mathrm{d} \pi$ bond with transition metals. It also forms hydride, which is a strongest base among the hydrides of other group members that form $d \pi-d \pi$ bond.
The atomic number of the element is _______ .
Explanation:
Phosphorus, an element from group 15 of the periodic table, can form a $d \pi-d \pi$ bond with transition metals. Among the hydrides of group 15, phosphine ($\text{PH}_3$) is considered the strongest base, except for ammonia ($\text{NH}_3$).
Number of oxygen atoms present in chemical formula of fuming sulphuric acid is ___________.
Explanation:
Fuming sulfuric acid, often known as oleum, can be represented chemically using the formula $ H_2S_2O_7 $. This compound is formed by adding excess sulfur trioxide ($ SO_3 $) to sulfuric acid ($ H_2SO_4 $). The chemical reaction can be represented as follows:
$ H_2SO_4 + SO_3 \rightarrow H_2S_2O_7 $
From the formula $ H_2S_2O_7 $, to determine the number of oxygen atoms, we look directly at the subscript corresponding to oxygen in the chemical formula. In this case, the subscript is 7, which indicates that there are 7 oxygen atoms present in the molecule of fuming sulfuric acid.
$\mathrm{Cl}_2 \mathrm{O}_7, \mathrm{CO}, \mathrm{PbO}_2, \mathrm{~N}_2 \mathrm{O}, \mathrm{NO}, \mathrm{Al}_2 \mathrm{O}_3, \mathrm{SiO}_2, \mathrm{~N}_2 \mathrm{O}_5, \mathrm{SnO}_2$
Explanation:
An amphoteric oxide is one that displays both acidic and basic properties; such substances react with both acids and bases. In the p-block, several elements can form amphoteric oxides, particularly those elements that are metallic or metalloid in nature. It's essential to recognize which oxides among the provided list have an amphoteric character:
- $\mathrm{Cl}_2 \mathrm{O}_7$ - This is dichlorine heptoxide, an oxide of chlorine, and shows acidic properties. It is not amphoteric.
- $\mathrm{CO}$ - Carbon monoxide does not behave as an acidic or basic oxide; it is mainly a neutral oxide.
- $\mathrm{PbO}_2$ - Lead(IV) oxide, also known as plumbic oxide. This oxide of lead is amphoteric, but it is much less common and less amphoteric than lead(II) oxide, PbO.
- $\mathrm{N}_2 \mathrm{O}$ - Nitrous oxide is a neutral oxide; it does not exhibit acidic or basic properties.
- $\mathrm{NO}$ - Nitric oxide, like N2O, is a neutral oxide.
- $\mathrm{Al}_2 \mathrm{O}_3$ - Aluminium oxide is well known for being amphoteric. It reacts with both acids and bases to produce salts and water.
- $\mathrm{SiO}_2$ - Silicon dioxide is generally acidic. Although it does not react with water to form an acidic solution, it will react with basic oxides. Therefore, it is typically not considered amphoteric.
- $\mathrm{N}_2 \mathrm{O}_5$ - Dinitrogen pentoxide is an acidic oxide; it is the anhydride of nitric acid.
- $\mathrm{SnO}_2$ - Tin dioxide, also known as stannic oxide. This oxide of tin is amphoteric, reacting with both acids and bases.
From the list, the amphoteric oxides are:
- $\mathrm{PbO}_2$ - Lead(IV) oxide (less commonly amphoteric compared to PbO)
- $\mathrm{Al}_2 \mathrm{O}_3$ - Aluminium oxide
- $\mathrm{SnO}_2$ - Tin dioxide
So, the number of amphoteric oxides in the list provided is 3.
1 mole of $\mathrm{PbS}$ is oxidised by "$\mathrm{X}$" moles of $\mathrm{O}_3$ to get "$\mathrm{Y}$" moles of $\mathrm{O}_2$. $\mathrm{X}+\mathrm{Y}=$ _________.
Explanation:
$\begin{aligned} & \mathrm{PbS}+4 \mathrm{O}_3 \rightarrow \mathrm{PbSO}_4+4 \mathrm{O}_2 \\ & \mathrm{x}=4, \mathrm{y}=4 \end{aligned}$
