iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 28th June Morning Shift
Given below are two statements :
Statement I : The pentavalent oxide of group-15 element, E2O5, is less acidic than trivalent oxide, E2O3, of the same element.
Statement II : The acidic character of trivalent oxide of group 15 elements, E2O3, decreases down the group.
In light of the above statements, choose most appropriate answer from the options given below :
A.
Both Statement I and Statement II are true.
B.
Both Statement I and Statement II are false.
C.
Statement I is true, but Statement II is false.
D.
Statement I is false, but Statement II is true.
Correct Answer: D
Explanation:
As +ve oxidation state increases, EN of element
increases hence acidic character increases. Down
the group, non-metallic character decreases, acidic
character decreases.
Acidic character : E2O5 > E2O3
Down the group, acidic character of E2O3 decreases.
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 27th June Evening Shift
The gas produced by treating an aqueous solution of ammonium chloride with sodium nitrite is :
A.
NH3
B.
N2
C.
N2O
D.
Cl2
Correct Answer: B
Explanation:
N2 gas is produced by treating an aqueous solution
of ammonium chloride with sodium nitrite.
NH4Cl + NaNO2 → NaCl + N2 (g) ↑ + 2H2O
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 27th June Evening Shift
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : Fluorine forms one oxoacid.
Reason R : Fluorine has smallest size amongst all halogens and is highly electronegative.
In the light of the above statements, choose the most appropriate answer from the options given below :
A.
Both A and R are correct and R is the correct explanation of A.
B.
Both A and R are correct but R is NOT the correct explanation of A.
C.
A is correct but R is not correct.
D.
A is not correct but R is correct.
Correct Answer: A
Explanation:
Due to its smaller size, fluorine forms only one oxoacid.
Both the Assertion and Reason are correct and The reason is the correct explanation.
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 27th June Morning Shift
Match List - I with List - II.
List - I (Si-Compounds)
List - II (Si-Polymeric/Other Products
(A)
${(C{H_3})_4}Si$
(I)
Chain Silicone
(B)
$(C{H_3})Si{(OH)_3}$
(II)
Dimeric Silicone
(C)
${(C{H_3})_2}Si{(OH)_2}$
(III)
Silane
(D)
${(C{H_3})_3}Si(OH)$
(IV)
2D - Silicone
Choose the correct answer from the options given below :
A.
(A) - (III), (B) - (II), (C) - (I), (D) - (IV)
B.
(A) - (IV), (B) - (I), (C) - (II), (D) - (III)
C.
(A) - (II), (B) - (I), (C) - (IV), (D) - (III)
D.
(A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Correct Answer: D
Explanation:
(CH3)4Si is a silane.
(CH3)Si(OH)3 polymerise to form 2D silicone.
(CH3)2Si(OH)2 polymerise to form chain silicone.
(CH3)3Si(OH) form dimer (CH3)3Si-O-Si(CH3)3
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 27th June Morning Shift
Heating white phosphorus with conc. NaOH solution gives mainly :
A.
Na3P and H2O
B.
H3PO and NaH
C.
P(OH)3 and NaH2PO4
D.
PH3 and NaH2PO2
Correct Answer: D
Explanation:
P4 + 3NaOH + 3H2O $\to$ 3NaH2PO2 + PH3
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 26th June Evening Shift
Which of the following elements is considered as a metalloid?
A.
Sc
B.
Pb
C.
Bi
D.
Te
Correct Answer: D
Explanation:
Sc, Pb, Bi are metals
Te is a metalloid
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 26th June Evening Shift
The oxide which contains an odd electron at the nitrogen atom is :
A.
N2O
B.
NO2
C.
N2O3
D.
N2O5
Correct Answer: B
Explanation:
The oxide of nitrogen which contains odd electron
is NO2
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 26th June Morning Shift
Choose the correct stability order of group 13 elements in their + 1 oxidation state :
A.
Al < Ga < In < Tl
B.
Tl < In < Ga < Al
C.
Al < Ga < Tl < In
D.
Al < Tl < Ga < In
Correct Answer: A
Explanation:
Due to inert pair effect, stability of +3 oxidation state
decreases and that of +1 oxidation state increases
for (down the group) group 13 elements.
So, the correct order of stability of group 13
elements in their +1 oxidation state is Al < Ga < In
< Tl.
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 26th June Morning Shift
The correct order of melting points of hydrides of group 16 elements is :
A.
H2S < H2Se < H2Te < H2O
B.
H2O < H2S < H2Se < H2Te
C.
H2S < H2Te < H2Se < H2O
D.
H2Se < H2S < H2Te < H2O
Correct Answer: A
Explanation:
Hydride
M.P.
H2O
273 K
H2S
188 K
H2Se
208 K
H2Te
222 K
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 26th June Morning Shift
Consider the following reaction :
A + alkali $\to$ B (Major Product)
If B is an oxoacid of phosphorus with no P-H bond, then A is :
A.
White P4
B.
Red P4
C.
P2O3
D.
H3PO3
Correct Answer: B
Explanation:
Red P4 + Alkali $ \to $ H4P2O6 (No P–H bond)
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 25th June Evening Shift
The number of bridged oxygen atoms present in compound B formed from the following reactions is
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 24th June Evening Shift
PCl5 is well known, but NCl5 is not. because,
A.
nitrogen is less reactive than phosphorus.
B.
nitrogen doesn't have d-orbitals in its valence shell.
C.
catenation tendency is weaker in nitrogen than phosphorus.
D.
size of phosphorus is larger than nitrogen.
Correct Answer: B
Explanation:
$\mathrm{PCl}_{5}$ is well known but $\mathrm{NCl}_{5}$ is not because nitrogen does not have vacant d-orbitals in its valence shell.
So, nitrogen cannot expand its octet. On the other hand, phosphorus has vacant $\mathrm{d}$-orbitals in its valence shell which enables it to expand its octet.
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 24th June Morning Shift
Identify the correct statement for B2H6 from those given below :
(A) In B2H6, all B-H bonds are equivalent.
(B) In B2H6, there are four 3-centre-2-electron bonds.
(C) B2H6 is a Lewis acid.
(D) B2H6 can be synthesized from both BF3 and NaBH4.
(E) B2H6 is a planar molecule.
Choose the most appropriate answer from the options given below :
A.
(A) and (E) only
B.
(B), (C) and (E) only
C.
(C) and (D) only
D.
(C) and (E) only
Correct Answer: C
Explanation:
It has two 3-centre-2-electron bonds and four
2-centre-2-electron bonds.
Hence, all B–H bonds are not equivalent.
It is an electron deficient compound as the octet of
boron is incomplete.
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 24th June Morning Shift
The most stable trihalide of nitrogen is :
A.
NF3
B.
NCl3
C.
NBr3
D.
NI3
Correct Answer: A
Explanation:
The
stability of trihalides decreases down the group due
to weakening of N – X bond and inability of N to
accommodate large sized halogen atoms (Cl, Br, I)
around it.
2022
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2022 (Online) 24th June Morning Shift
Which one of the following elemental forms is not present in the enamel of the teeth?
A.
Ca2+
B.
P3+
C.
F$-$
D.
P5+
Correct Answer: B
Explanation:
$\mathrm{P}^{+3}$ is not present is enamel of teeth.
Th compound present is $\left[3 \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2} \cdot \mathrm{CaF}_{2}\right]$
Which contains $\mathrm{Ca}^{+2}, \mathrm{P}^{+5}$ & $\mathrm{F}^{-}$
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 1st September Evening Shift
The oxide without nitrogen-nitrogen bond is :
A.
N2O
B.
N2O4
C.
N2O3
D.
N2O5
Correct Answer: D
Explanation:
(a) N $ \equiv $ N+ $-$ O$-$
(b) (c) (d)
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 31st August Evening Shift
Which one of the following correctly represents the order of stability of oxides, X2O; (X = halogen)?
A.
Br > Cl > I
B.
Br > I > Cl
C.
Cl > I > Br
D.
I > Cl > Br
Correct Answer: D
Explanation:
Stability of oxides of Halogens is
I > Cl > Br
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 31st August Evening Shift
The number of S = O bonds present in sulphurous acid, peroxodisulphuric acid and pyrosulphuric acid, respectively are :
A.
2, 3 and 4
B.
1, 4 and 3
C.
2, 4 and 3
D.
1, 4 and 4
Correct Answer: D
Explanation:
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 27th August Evening Shift
Which one of the following is formed (mainly) when red phosphorus is heated in a sealed tube at 803 K?
A.
White phosphorus
B.
Yellow phosphorus
C.
$\beta$-Black phosphorus
D.
$\alpha$-Black phosphorus
Correct Answer: D
Explanation:
When red phosphorus is heated in a sealed tube at 803 K, $\alpha$-Black phosphorus is formed.
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 27th August Morning Shift
In which one of the following molecules strongest back donation of an electron pair from halide to boron is expected?
(d) Orthophosphorous acid : ${H_3}\underline P {O_3}$
(+1)3 + x + (–2)3 = 0
x = +3
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 26th February Evening Shift
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : In TlI3, isomorphous to CsI3, the metal is present in +1 oxidation state.
Reason R : Tl metal has fourteen f electrons in its electronic configuration.
In the light of the above statements, choose the most appropriate answer from the options given below :
A.
A is correct but R is not correct
B.
A is not correct but R is correct
C.
Both A and R are correct but R is NOT the correct explanation of A
D.
Both A and R are correct and R is the correct explanation of A
Correct Answer: C
Explanation:
A : Due to inert pair effect, Tl is more stable in
+1 oxidation state
Hence TlI3 and CSI3 are isomorphous
R : Electronic configuration of Tl (81) =
[Xe] 4f14 5d10 6s2 6p1
Both A and R are correct but R is not the
correct explanation of A.
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 26th February Morning Shift
Find A, B and C in the following reactions :
$N{H_3} + A + C{O_2} \to {(N{H_4})_2}C{O_3}$
${(N{H_4})_2}C{O_3} + {H_2}O + B \to N{H_4}HC{O_3}$
$N{H_4}HC{O_3} + NaCl \to N{H_4}Cl + C$
A.
$A - {O_2};B - C{O_2};C - N{a_2}C{O_3}$
B.
$A - {H_2}O;B - {O_2};C - NaHC{O_3}$
C.
$A - {H_2}O;B - {O_2};C - N{a_2}C{O_3}$
D.
$A - {H_2}O;B - C{O_2};C - NaHC{O_3}$
Correct Answer: D
Explanation:
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 26th February Morning Shift
On treating a compound with warm dil. H2SO4, gas X is evolved which turns K2Cr2O7 paper acidified with dil. H2SO4 to a green compound Y. X and Y respectively are :
at room temperature $\alpha $-sulphur (Rhombic) is most stable form.
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 25th February Morning Shift
The correct statement about B2H6 is :
A.
Its fragment, BH3, behaves as a Lewis base.
B.
All B$-$H$-$B angles are of 120$^\circ$.
C.
The two B$-$H$-$B bonds are not of same length.
D.
Terminal B$-$H bonds have less p-character when compared to bridging bonds.
Correct Answer: D
Explanation:
Terminal B – H bonds are shorter than the
bridging B – H bonds which shows that the
terminal B – H bonds have greater s-character
and less p-character.
2021
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2021 (Online) 24th February Morning Shift
Al2O3 was leached with alkali to get X. The solution of X on passing of gas Y, forms Z.
X, Y and Z respectively are :
A.
X = Na[Al(OH)4], Y = CO2, Z = Al2O3.xH2O
B.
X = Al(OH)3, Y = CO2, Z = Al2O3
C.
X = Al(OH)3, Y = SO2, Z = Al2O3.xH2O
D.
X = Na[Al(OH)4], Y = SO2, Z = Al2O3
Correct Answer: A
Explanation:
Al2O3 (aluminium oxide) was leached with alkali to get
Na[Al(OH)4] (X) (sodium aluminate). The solution of sodium
aluminate when passed through gas Y, i.e. carbon dioxide (CO2)
forms Al2O3.xH2O (Z).
Complete reactions are as follows
2020
JEE Mains
MCQ
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2020 (Online) 6th September Evening Slot
iCON Education HYD, 79930 92826, 73309 72826JEE Main 2020 (Online) 6th September Evening Slot
Reaction of an inorganic sulphite X with dilute
H2SO4 generates compound Y. Reaction of Y
with NaOH gives X. Further, the reaction of X
with Y and water affords compound Z. Y and Z,
respectively, are :