Aldehydes, Ketones and Carboxylic Acids
Natural rubber on complete ozonolysis $\left(\mathrm{O}_3 / \mathrm{Zn}-\mathrm{H}_2 \mathrm{O}\right)$ gives compound $\mathbf{X}$ as the major product. $\mathbf{X}$ gives positive iodoform and Tollen's tests. $\mathbf{X}$ on heating with aqueous NaOH gives $\mathbf{Y}$ as the major product. $\mathbf{Y}$ is
Considering LiBH4 reduces an ester group to the corresponding alcohol and does not reduce a carboxylic acid group, the correct statement about the major products P, Q, R and S is:
P & Q are identical, and R & S are diastereomers.
P & Q are diastereomers, and R & S are identical.
P & Q are diastereomers, and R & S are diastereomers.
P & Q are identical, and R & S are identical.
The List-II contains products obtained from the reaction of compounds in List-I with $O_3$/Zn-$H_2O$ followed by cyclization (via more stable enolate) in the presence of aqueous NaOH. Match each entry in List-I with appropriate entry in List-II and choose the correct option.
| List-I | List-II |
|---|---|
(P)
|
(1)
|
(Q)
|
(2)
|
(R)
|
(3)
|
(S)
|
(4)
|
(5)
|
P $\rightarrow$ 2; Q $\rightarrow$ 4; R $\rightarrow$ 1; S $\rightarrow$ 3
P $\rightarrow$ 3; Q $\rightarrow$ 4; R $\rightarrow$ 5; S $\rightarrow$ 2
P $\rightarrow$ 2; Q $\rightarrow$ 1; R $\rightarrow$ 5; S $\rightarrow$ 3
P $\rightarrow$ 3; Q $\rightarrow$ 5; R $\rightarrow$ 4; S $\rightarrow$ 2
Match the major products obtained in the reactions given in List-I with the corresponding structures in List-II and choose the correct option.
| List-I | List-II |
|---|---|
(P)
|
(1)
|
(Q)
|
(2)
|
(R)
|
(3)
|
(S)
|
(4)
|
(5)
|
P $\rightarrow$ 2; Q $\rightarrow$ 1; R $\rightarrow$ 5; S $\rightarrow$ 4
P $\rightarrow$ 1; Q $\rightarrow$ 2; R $\rightarrow$ 4; S $\rightarrow$ 5
P $\rightarrow$ 1; Q $\rightarrow$ 2; R $\rightarrow$ 3; S $\rightarrow$ 4
P $\rightarrow$ 2; Q $\rightarrow$ 1; R $\rightarrow$ 3; S $\rightarrow$ 5
In the following reaction sequence, Q, R, S and T are the major products.
The correct statement(s) about Q, R, S and T is(are) :
S on warming with ammoniacal AgNO3 results in the formation of silver mirror.
Q on treatment with Cl2(excess)/UV gives gammaxane.
T is a heterocyclic compound.
R on acid catalyzed intramolecular cyclization followed by treatment with Zn-Hg/HCl gives 9,10-dihydroxyanthracene.
The sum of total number of carbonyl groups ($> {C}= {O}$) present in the major products X and Y in the following reactions is _____.
Explanation:
Number of $>C=O$ groups in $(X)$ and $(Y)$ are 1 and 3 respectively. $(1+3=4)$
Monocyclic compounds $\mathbf{P}, \mathbf{Q}, \mathbf{R}$ and $\mathbf{S}$ are the major products formed in the reaction sequences given below.
The product having the highest number of unsaturated carbon atom(s) is :
P
Q
R
S
In the following reaction sequence, the major product $\mathbf{Q}$ is
List-I contains various reaction sequences and List-II contains the possible products. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.
| List-I | List-II |
|---|---|
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An organic compound $\mathbf{P}$ having molecular formula $\mathrm{C}_6 \mathrm{H}_6 \mathrm{O}_3$ gives ferric chloride test and does not have intramolecular hydrogen bond. The compound $\mathbf{P}$ reacts with 3 equivalents of $\mathrm{NH}_2 \mathrm{OH}$ to produce oxime $\mathbf{Q}$. Treatment of $\mathbf{P}$ with excess methyl iodide in the presence of $\mathrm{KOH}$ produces compound $\mathbf{R}$ as the major product. Reaction of $\mathbf{R}$ with excess iso-butylmagnesium bromide followed by treatment with $\mathrm{H}_3 \mathrm{O}^{+}$gives compound $\mathbf{S}$ as the major product.
The total number of methyl $\left(-\mathrm{CH}_3\right)$ group(s) in compound $\mathbf{S}$ is ___.
Explanation:
$\therefore$ Sum of oxygen atoms in $\mathrm{S}$ and $\mathrm{T}=1+1=2$
Explanation:
$\begin{aligned} & \text { Molecular mass of polymers }=(104 \times 500)+(118 \times 500)-18 \times 999 \\\\ & =52000+59000-17982=93018\end{aligned}$
Complete reaction of acetaldehyde with excess formaldehyde, upon heating with conc. $\mathrm{NaOH}$ solution, gives $\mathbf{P}$ and $\mathbf{Q}$. Compound $\mathbf{P}$ does not give Tollens' test, whereas $\mathbf{Q}$ on acidification gives positive Tollens' test. Treatment of $\mathbf{P}$ with excess cyclohexanone in the presence of catalytic amount of $p$-toluenesulfonic acid (PTSA) gives product $\mathbf{R}$.
Sum of the number of methylene groups $\left(-\mathrm{CH}_2-\right)$ and oxygen atoms in $\mathbf{R}$ is __________.
Explanation:
Number of $\mathrm{CH}_2$ groups in $\mathrm{R}=14$
Number of $\mathrm{O}$-atoms $=4$
Required Answer $=14+4=18$
| List - I | List - II |
|---|---|
| (P) Etard reaction | (1) Acetophenone $\stackrel{\mathrm{Zn}-\mathrm{Hg}, \mathrm{HCl}}{\longrightarrow}$ |
| (Q) Gattermann reaction | (2) $ \text { Toluene } \underset{\text { (ii) } \mathrm{SOCl}_2}{\stackrel{\text { (i) } \mathrm{KMnO}_4, \mathrm{KOH}, \Delta}{\longrightarrow}} $ |
| (R) Gattermann-Koch reaction | (3) $ \text { Benzene } \underset{\text { anhyd. } \mathrm{AlCl}_3}{\stackrel{\mathrm{CH}_3 \mathrm{Cl}}{\longrightarrow}} $ |
| (S) Rosenmund reduction | (4) $ \text { Aniline } \underset{273-278 \mathrm{~K}}{\stackrel{\mathrm{NaNO}_2 / \mathrm{HCl}}{\longrightarrow}} $ |
| (5) $ \text { Phenol } \stackrel{\mathrm{Zn}, \Delta}{\longrightarrow} $ |
The correct statement(s) about $\mathbf{P}, \mathbf{Q}, \mathbf{R}$, and $\mathbf{S}$ is(are) :
The correct statement(s) about $\mathbf{P}, \mathbf{Q}, \mathbf{R}$, and $\mathbf{S}$ is(are) :
Considering the reaction sequence given below, the correct statement(s) is(are)
Explanation:
Carbonyl compounds react with NH2OH to give oximes.
There are four sp2-carbon atoms, four sp2-nitrogen atoms and four sp2-oxygen atoms as shown in structures I and II.
Therefore, total number of atoms having sp2-hybridisation are twelve (12).
What is the degree of unsaturation of Q?
Explanation:
Number of rings = 4 + 1 = 5
$\pi $-bonds = 4 $ \times $ 3 + 1 = 13
Thus, the degree of unsaturation of Q is 18.
The correct structure of
Consider Q, R and S as major products.
The correct option is
The compound S is
The compound R is
(Atomic weights in $g\,mo{l^{ - 1}}:H = 1,C = 12,$ $N = 14,O = 16,$ $Br = 80.$. The yield (%) corresponding to the product in each step is given in the parenthesis)
Explanation:
The amount of D formed in mol is ${{60} \over {100}} \times {{50} \over {100}} \times {{50} \over {100}} \times 10 = 1.5$ mol
Amount of D in grams is = 1.5 $\times$ 330 g = 495 g
and anhydrous $\mathrm{AlCl}_3$.
The option(s) with suitable combination of $P$ and $R,$ respectively, is (are)
The correct order of acidity for the following compounds is
The major product of the following reaction sequence is:
Reagent(s) which can be used to bring about the following transformation is(are)
The correct statements about of the following reaction sequence is (are)
Cumene (C9H12) $\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{(ii)\,{H_3}{O^ + }}^{(i)\,{O_2}}} $ P $\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{}^{CHC{l_3}/NaOH}} $ Q (major) + R (minor)
Q $\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{PhC{H_2}Br}^{NaOH}} $ S
Among the following the number of reactions that produces benzaldehyde is _________.
Explanation:
Therefore, the number of reactions leading to the formation of benzaldehyde is 4.
In the following reactions
Compound X is
In the following reactions
The major compound Y is
The major product of the following reaction is
The major product in the following reaction is
Different possible thermal decomposition pathways for peroxyesters are shown below. Match each pathway from List I with an appropriate structure from List II and select the correct answer using the code given below the lists.
Explanation:
Compounds formed from P and Q are, respectively,
