p-Block Elements

AgCl is insoluble in dil. nitric acid.

Option A: O₃ molecule is bent

✅ True

• The structure of ozone (O₃) is angular (bent) with a bond angle of about 117°.

• It has resonance structures and sp²-hybridized central oxygen.

Option B: Ozone is violet-black in solid state

✅ True

• In solid state, ozone is violet-black.

• In liquid state, ozone is dark blue.

• In gas state, it is pale blue.

Option C: Ozone is diamagnetic gas

✅ True

• Although O₂ is paramagnetic, ozone (O₃) has all paired electrons, hence diamagnetic.

Option D: ONCl and ONO⁻ are isoelectronic

❌ False

Let’s check the total number of electrons:

• ONCl:

  O (8) + N (7) + Cl (17) = 32 electrons

• ONO⁻:

  O (8×2 = 16) + N (7) + 1 (extra for negative charge) = 24 electrons

→ They are not isoelectronic.

✅ Correct answer: Option D is the wrong statement.

To determine which of the given reactions of Xenon compounds is not feasible, we can analyze each option based on the chemical properties and reactivity of the substances involved :

1. Option A :
   $ \text{XeO}_3 + 6\text{HF} \to \text{XeF}_6 + 3\text{H}_2\text{O} $ This reaction involves the conversion of xenon trioxide to xenon hexafluoride. While both compounds are known, the direct conversion of XeO₃ to XeF₆ is not typically feasible due to the different oxidation states of xenon in these compounds and the reaction conditions required.

2. Option B :
   $ \text{XeF}_6 + \text{RbF} \to \text{Rb}[\text{XeF}_7] $ This reaction represents the formation of a rubidium heptafluoroxenate(VII) compound. XeF₆ can react with RbF to form Rb[XeF₇], which is a known compound. This reaction is feasible.

3. Option C :
   $ 2\text{XeF}_2 + 2\text{H}_2\text{O} \to 2\text{Xe} + 4\text{HF} + \text{O}_2 $ In this reaction, xenon difluoride is reacting with water to produce xenon, hydrofluoric acid, and oxygen. XeF₂ is known to hydrolyze in the presence of water to produce these products, making this reaction feasible.

4. Option D :
   $ 3\text{XeF}_4 + 6\text{H}_2\text{O} \to 2\text{Xe} + \text{XeO}_3 + 12\text{HF} + 1.5\text{O}_2 $ This reaction suggests that xenon tetrafluoride reacts with water to form xenon, xenon trioxide, hydrofluoric acid, and oxygen. The formation of XeO₃ and O₂ in this reaction is feasible as XeF₄ can undergo hydrolysis under certain conditions.

Given these considerations, Option A is the least feasible reaction among the ones listed. The direct conversion of XeO₃ to XeF₆ is not commonly reported or expected under normal chemical reaction conditions.