
The correct sequence of reagents for the preparation of Q and R is :
Find out the major products from the following reactions.

In the following given reaction, 'A' is

$ \stackrel{\bullet}{\mathrm{Cl}}+\mathrm{CH}_{4} \rightarrow \mathrm{A}+\mathrm{B} $
A and B in the above atmospheric reaction step are :
Major product of the following reaction is

A compound ‘$\mathrm{A}$’ on reaction with ‘$\mathrm{X}$’ and ‘$\mathrm{Y}$’ produces the same major product but different by product '$a$' and '$b^{\prime}$. Oxidation of '$a$' gives a substance produced by ants.

'X' and 'Y' respectively are
Two isomers 'A' and 'B' with molecular formula C4H8 give different products on oxidation with KMnO4 in acidic medium. Isomer 'A' on reaction with KMnO4/H+ results in effervescence of a gas and gives ketone. The compound 'A' is
What will be the major product of following sequence of reactions?

Product 'A' of following sequence of reactions is

The major product in the following reaction

The product formed in the following reaction.

Given below are two statements :
Statement I : The presence of weaker $\pi$-bonds make alkenes less stable than alkanes.
Statement II : The strength of the double bond is greater than that of carbon-carbon single bond.
In the light of the above statements, choose the correct answer from the options given below :
Which of the following reagents / reactions will convert 'A' to 'B' ?

(ii) Cl2, HCl
(iii) NaNO2, HCl, 0$^\circ$C
(iv) H2O/H+
(ii) NaNO2, HCl, 0$^\circ$C
(iii) H2O/H+
(iv) Cl2, FeCl3
(ii) Fe, HCl
(iii) NaNO2, HCl, 0$^\circ$C
(iv) H2O/H+
(ii) NaNO2, HCl, 0$^\circ$C
(iii) Fe, HCl
(iv) H2O/H+
CH4 + I2 $\mathrel{\mathop{\kern0pt\rightleftharpoons} \limits_{{\mathop{\rm Re}\nolimits} versible}^{hv}} $ CH3 $-$ I + HI
Compound 'A' also yields compound 'B' an ozonolysis. Compound 'A' is :

Major product P of above reaction, is :

For above chemical reactions, identify the correct statement from the following :
List - I (Chemicals)
(a) Alcoholic potassium hydroxide
(b) Pd/BaSO4
(c) BHC (Benzene hexachloride)
(d) Polyacetylene
List - II (Use / Preparation / Constituent)
(i) Electrodes in batteries
(ii) Obtained by addition reaction
(iii) Used for $\beta$ - elimination reaction
(iv) Lindlar's catalyst
Choose the most appropriate match :

Statement I : 2-methylbutane on oxidation with KMnO4 gives 2-methylbutan-2-ol.
Statement II : n-alkanes can be easily oxidised to corresponding alcohols with KMnO4.
Choose the correct option :

${\left( {C{H_3}} \right)_3}CCH\left( {OH} \right)C{H_3}\buildrel {conc.\,\,\,{H_2}S{O_4}} \over \longrightarrow $
${\left( {C{H_3}} \right)_2}CHCH\left( {Br} \right)C{H_3}\buildrel {alc.\,\,KOH} \over \longrightarrow $
${\left( {C{H_3}} \right)_2}{\rm{ }}CHCH\left( {Br} \right)C{H_3}\buildrel {{{(C{H_3})}_3}{O^\Theta }{K^ \oplus }} \over \longrightarrow $
${\left( {C{H_3}} \right)_2}\mathop C\limits_{\mathop |\limits_{OH} } - C{H_2} - CHO\buildrel \Delta \over \longrightarrow $
Which of these reaction(s) will not produce Saytzeff product ?
'A' is :
H3C–CH=CH2 $\buildrel {C{l_2}/{H_2}O} \over \longrightarrow $





















