d and f Block Elements

Between AgCl and AgI, AgI is less soluble, hence ammonia can dissolve ppt. of AgCl only due to formation of complex as given below:

AgCl + 2NH₃ $ \to $ [Ag(NH₃)₂]Cl

$AgN{O_3}$ on heating till red hot decomposes as follows:

$AgN{O_3} \to Ag + N{O_2} + {1 \over 2}{O_2}$

Due to stable electronic configuration of Cr⁺¹ ion (3d⁵)

It is mercury because it exists as liquid at room temperature.

Ionic radili $ \propto {1 \over z}$

Thus, ${{{z_2}} \over {{z_1}}} \Rightarrow {{1.06} \over {\left( {Ionic\,\,\,radii\,\,\,of\,\,L{u^{3 + }}} \right)}} = {{71} \over {57}}$

$ \Rightarrow \,\,\,$ Ionic radii of $L{u^{3 + }} = 0.85\,\mathop A\limits^ \circ $

FeCl₃ + 3NH₄OH $ \to $ Fe(OH)₃ ↓(reddish brown) + 3NH₄Cl

CrCl₃ + 3NH₄OH $ \to $ Cr(OH)₃ (Bluish green) + 3NH₄Cl

Common oxidation states of $Ce$(Cerium) are $+3$ and $+4$

$M{n^{ + + }} - 5\,\,$ unpaired electrons

$F{e^{ + + }} - 4\,\,$ unpaired electrons

$T{i^{ + + }}$$ - 2\,\,$ unpaired electrons

$C{r^{ + + }} - 4\,\,$ unpaired electrons

hence maximum no. of unpaired electron is present in $M{n^{ + + }}.$

NOTE : Magnetic moment $ \propto $ number of unpaired electrons