iCON Education - Newton's Laws of Motion

Q1 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find acceleration of blocks and the normal force between them.

A.

$a = \frac{10}{7} \, \text{m/s}^2, N = \frac{50}{7} \, \text{N}$

B.

$a = \frac{20}{7} \, \text{m/s}^2, N = \frac{100}{7} \, \text{N}$

C.

$a = \frac{20}{7} \, \text{m/s}^2, N = \frac{50}{7} \, \text{N}$

D.

$a = \frac{10}{7} \, \text{m/s}^2, N = \frac{100}{7} \, \text{N}$

Correct Answer: B

Explanation:

For the $2 \, \text{kg}$ block, the equation of motion is $20 - N = 2a$
For the $5 \, \text{kg}$ block, the equation of motion is $N = 5a$
Substituting $N = 5a$ into the first equation gives $20 - 5a = 2a$, which leads to $7a = 20$
Solving for acceleration gives $a = \frac{20}{7} \, \text{m/s}^2$
Substituting the value of $a$ back into $N = 5a$ gives $N = 5 \times \frac{20}{7} = \frac{100}{7} \, \text{N}$

Q2 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find acceleration of the blocks and the normal force between them.

A.

$a = 4 \, \text{m/s}^2, N = 12 \, \text{N}$

B.

$a = 2 \, \text{m/s}^2, N = 10 \, \text{N}$

C.

$a = 3 \, \text{m/s}^2, N = 14 \, \text{N}$

D.

$a = 5 \, \text{m/s}^2, N = 16 \, \text{N}$

Q3 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find acceleration of blocks and normal force between 3Kg and 5Kg blocks.

A.

$a = 4 \, \text{m/s}^2, N = 40 \, \text{N}$

B.

$a = 2 \, \text{m/s}^2, N = 35 \, \text{N}$

C.

$a = 4 \, \text{m/s}^2, N = 50 \, \text{N}$

D.

$a = 6 \, \text{m/s}^2, N = 60 \, \text{N}$

Q4 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the interaction force between the $3 \, \text{kg}$ and $4 \, \text{kg}$ blocks.

A.

$15 \, \text{N}$

B.

$29 \, \text{N}$

C.

$35 \, \text{N}$

D.

$45 \, \text{N}$

Correct Answer: B

Explanation:

Total mass of the system $m_{total} = 2 + 3 + 4 = 9 \, \text{kg}$
Net force acting on the system $F_{net} = 54 - 9 = 45 \, \text{N}$
System acceleration $a = \frac{45}{9} = 5 \, \text{m/s}^2$
Considering the motion of the $4 \, \text{kg}$ block, let the interaction force between the $3 \, \text{kg}$ and $4 \, \text{kg}$ blocks be $N$
$N - 9 = 4 \times 5$
$N = 9 + 20 = 29 \, \text{N}$

Q5 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the contact force between the $10 \, \text{kg}$ and $20 \, \text{kg}$ blocks.

A.

$10 \, \text{N}$

B.

$0 \, \text{N}$

C.

$30 \, \text{N}$

D.

$60 \, \text{N}$

Correct Answer: B

Explanation:

Total mass of the system $m_{total} = 10 + 20 = 30 \, \text{kg}$
Total net force acting in the same direction $F_{net} = 10 + 20 = 30 \, \text{N}$
System acceleration $a = \frac{30}{30} = 1 \, \text{m/s}^2$
Considering the $10 \, \text{kg}$ block, the equation of motion is $10 - N = 10 \times 1$
$10 - N = 10$
$N = 0 \, \text{N}$

Q6 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find acceleration of each block and tension in the string.

A.

$a = 10 \, \text{m/s}^2, T = 30 \, \text{N}$

B.

$a = 20 \, \text{m/s}^2, T = 40 \, \text{N}$

C.

$a = 15 \, \text{m/s}^2, T = 25 \, \text{N}$

D.

$a = 25 \, \text{m/s}^2, T = 50 \, \text{N}$

Q7 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration of the system and the tensions $T_1$ and $T_2$ in the strings.

A.

$a = 10 \, \text{m/s}^2, T_1 = 20 \, \text{N}, T_2 = 50 \, \text{N}$

B.

$a = 5 \, \text{m/s}^2, T_1 = 10 \, \text{N}, T_2 = 25 \, \text{N}$

C.

$a = 15 \, \text{m/s}^2, T_1 = 30 \, \text{N}, T_2 = 60 \, \text{N}$

D.

$a = 20 \, \text{m/s}^2, T_1 = 40 \, \text{N}, T_2 = 80 \, \text{N}$

Correct Answer: A

Explanation:

$a = \frac{70 - 0}{2 + 3 + 2} = 10$
$T_1 = 2 \times a = 2 \times 10 = 20$
$T_2 - T_1 = 3a$
$T_2 - 20 = 3 \times 10$
$T_2 = 50 \, \text{N}$

Q8 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the tensions $T_1$ and $T_2$.

A.

$T_1 = 36 \, \text{N}, T_2 = 60 \, \text{N}$

B.

$T_1 = 20 \, \text{N}, T_2 = 40 \, \text{N}$

C.

$T_1 = 40 \, \text{N}, T_2 = 50 \, \text{N}$

D.

$T_1 = 30 \, \text{N}, T_2 = 70 \, \text{N}$

Correct Answer: A

Explanation:

$a = \frac{100 - 20}{2 + 3 + 5} = 8$
$T_1 - 20 = 2 \times 8$
$T_1 = 36$
$100 - T_2 = 5 \times 8$
$T_2 = 60$

Q9 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

from the image given below Find the acceleration of the system and the contact force between (i) $2\text{ kg}$ and $3\text{ kg}$ blocks (ii) $3\text{ kg}$ and $5\text{ kg}$ blocks

A.

$a = 1\text{ m/s}^2$, $N_{23} = 6\text{ N}$, $N_{35} = 5\text{ N}$

B.

$a = 1\text{ m/s}^2$, $N_{23} = 8\text{ N}$, $N_{35} = 5\text{ N}$

C.

$a = 2\text{ m/s}^2$, $N_{23} = 8\text{ N}$, $N_{35} = 5\text{ N}$

D.

$a = 1\text{ m/s}^2$, $N_{23} = 8\text{ N}$, $N_{35} = 6\text{ N}$

Correct Answer: B

Explanation:

Total mass of the system $m_{\text{total}} = 2\text{ kg} + 3\text{ kg} + 5\text{ kg} = 10\text{ kg}$
Applied force $F = 10\text{ N}$
Acceleration of the system $a = \frac{F}{m_{\text{total}}} = \frac{10}{10} = 1\text{ m/s}^2$
Contact force between $2\text{ kg}$ and $3\text{ kg}$ blocks pushes the $3\text{ kg}$ and $5\text{ kg}$ blocks, so $N_{1} = (3 + 5) \times a = 8 \times 1 = 8\text{ N}$
Contact force between $3\text{ kg}$ and $5\text{ kg}$ blocks pushes only the $5\text{ kg}$ block, so $N_{2} = 5 \times a = 5 \times 1 = 5\text{ N}$

Q10 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

from the image given below Calculate : (i) $a_{\text{system}}$ (ii) $F_{\text{DE}}$ (iii) $F_{\text{CD}}$ (iv) $F_{\text{BC}}$ (v) $F_{\text{AB}}$ corresponding to the following diagram.

A.

$a_{\text{system}} = \frac{P}{5m}$, $F_{\text{DE}} = \frac{P}{5}$, $F_{\text{CD}} = \frac{2P}{5}$, $F_{\text{BC}} = \frac{3P}{5}$, $F_{\text{AB}} = \frac{4P}{5}$

B.

$a_{\text{system}} = \frac{P}{m}$, $F_{\text{DE}} = \frac{P}{5}$, $F_{\text{CD}} = \frac{P}{3}$, $F_{\text{BC}} = \frac{P}{2}$, $F_{\text{AB}} = \frac{2P}{3}$

C.

$a_{\text{system}} = \frac{P}{5m}$, $F_{\text{DE}} = \frac{P}{2}$, $F_{\text{CD}} = \frac{P}{3}$, $F_{\text{BC}} = \frac{P}{4}$, $F_{\text{AB}} = \frac{P}{5}$

D.

$a_{\text{system}} = \frac{2P}{5m}$, $F_{\text{DE}} = \frac{P}{5}$, $F_{\text{CD}} = \frac{2P}{5}$, $F_{\text{BC}} = \frac{3P}{5}$, $F_{\text{AB}} = P$

Correct Answer: A

Explanation:

Total mass of the five identical blocks is $m_{\text{total}} = m + m + m + m + m = 5m$
The external force applied is $P$
The acceleration of the system is $a_{\text{system}} = \frac{P}{5m}$
The contact force $F_{\text{DE}}$ between block D and block E pushes only block E of mass $m$, so $F_{\text{DE}} = m \times a_{\text{system}} = \frac{P}{5}$
The contact force $F_{\text{CD}}$ between block C and block D pushes blocks D and E of combined mass $2m$, so $F_{\text{CD}} = 2m \times a_{\text{system}} = \frac{2P}{5}$
The contact force $F_{\text{BC}}$ between block B and block C pushes blocks C, D, and E of combined mass $3m$, so $F_{\text{BC}} = 3m \times a_{\text{system}} = \frac{3P}{5}$
The contact force $F_{\text{AB}}$ between block A and block B pushes blocks B, C, D, and E of combined mass $4m$, so $F_{\text{AB}} = 4m \times a_{\text{system}} = \frac{4P}{5}$

Q11 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

from the image given below Calculate T for the following diagram :

A.

$T = \frac{m_1 P}{m_1 + m_2}$

B.

$T = \frac{m_2 P}{m_1 + m_2}$

C.

$T = \frac{(m_1 + m_2)P}{m_1}$

D.

$T = \frac{P}{m_1 m_2}$

Correct Answer: B

Explanation:

Total mass of the system is $m_{\text{total}} = m_1 + m_2$
The external pulling force applied on the system is $P$
The acceleration of the system is $a = \frac{P}{m_1 + m_2}$
Considering the motion of block of mass $m_2$, the only horizontal force acting on it is the tension $T$
Applying Newton's second law to mass $m_2$, we get $T = m_2 a$
Substituting the expression for acceleration, we obtain $T = \frac{m_2 P}{m_1 + m_2}$

Q12 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

Two blocks of masses $2\text{ kg}$ and $3\text{ kg}$ connected by a string are pulled by forces $40\text{ N}$ to the left and $100\text{ N}$ to the right on a smooth horizontal surface. Find the acceleration of the system and the tension in the string connecting the blocks.

A.

Acceleration = $12\text{ m/s}^2$, Tension = $64\text{ N}$

B.

Acceleration = $10\text{ m/s}^2$, Tension = $50\text{ N}$

C.

Acceleration = $12\text{ m/s}^2$, Tension = $40\text{ N}$

D.

Acceleration = $8\text{ m/s}^2$, Tension = $64\text{ N}$

Q13 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

from the image given below Two blocks of mass $4\ kg$ and $6\ kg$ are placed in contact with each other on a frictionless horizontal surface. If we apply a push of $5\ N$ on the heavier mass, the force on the lighter mass will be

A.

$5\ N$

B.

$4\ N$

C.

$2\ N$

D.

None of the above

Q14 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

from the image given below In the above problem, if a push of $5\ N$ is applied on the lighter mass, the force exerted by the lighter mass on the heavier mass will be

A.

$5\ N$

B.

$4\ N$

C.

$3\ N$

D.

None of the above

Q15 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

from the image given below Two blocks are in contact on a frictionless table one has a mass $m$ and the other $2\ m$ as shown in figure. Force $F$ is applied on mass $2\ m$ then system moves towards right. Now the same force $F$ is applied on $m$. The ratio of force of contact between the two blocks will be in the two cases respectively.

A.

$1 : 3$

B.

$1 : 2$

C.

$1 : 1$

D.

$1 : 4$

Q16 DPT Contact Force and acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

from the image given below Three blocks of masses $2\ kg$, $3\ kg$ and $5\ kg$ are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force $F = 10\ N$, then tension $T_1 =$

A.

$1\ N$

B.

$5\ N$

C.

$8\ N$

D.

$10\ N$

Q17 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the mass $m$ if all masses are in equilibrium.

A.

$10 \, \text{kg}$

B.

$15 \, \text{kg}$

C.

$20 \, \text{kg}$

D.

$30 \, \text{kg}$

Q18 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the unknown masses $m_1$ and $m_2$ when all masses are in equilibrium.

A.

$m_1 = 10 \, \text{kg}, m_2 = 20 \, \text{kg}$

B.

$m_1 = 20 \, \text{kg}, m_2 = 40 \, \text{kg}$

C.

$m_1 = 30 \, \text{kg}, m_2 = 60 \, \text{kg}$

D.

$m_1 = 40 \, \text{kg}, m_2 = 80 \, \text{kg}$

Q19 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find $m_1$ and $m_2$ if all masses are in equilibrium.

A.

$m_1 = 10 \, \text{kg}, m_2 = 20 \, \text{kg}$

B.

$m_1 = 20 \, \text{kg}, m_2 = 10 \, \text{kg}$

C.

$m_1 = 20 \, \text{kg}, m_2 = 20 \, \text{kg}$

D.

$m_1 = 10 \, \text{kg}, m_2 = 10 \, \text{kg}$

Q20 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the mass $m$ on the inclined plane if all masses are in equilibrium.

A.

$40 \, \text{kg}$

B.

$60 \, \text{kg}$

C.

$80 \, \text{kg}$

D.

$100 \, \text{kg}$

Q21 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the unknown mass $m$ when all masses are in equilibrium.

A.

$5 \, \text{kg}$

B.

$10 \, \text{kg}$

C.

$15 \, \text{kg}$

D.

$20 \, \text{kg}$

Q22 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find $m_1$ and $m_2$ if all masses are in equilibrium.

A.

$m_1 = 10 \, \text{kg}, m_2 = 20 \, \text{kg}$

B.

$m_1 = 20 \, \text{kg}, m_2 = 10 \, \text{kg}$

C.

$m_1 = 30 \, \text{kg}, m_2 = 15 \, \text{kg}$

D.

$m_1 = 40 \, \text{kg}, m_2 = 20 \, \text{kg}$

Q23 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the unknown mass $m$ if all masses are in equilibrium.

A.

$15 \, \text{kg}$

B.

$30 \, \text{kg}$

C.

$45 \, \text{kg}$

D.

$60 \, \text{kg}$

Q24 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the unknown mass $m$ if all masses are in equilibrium.

A.

$30 \, \text{kg}$

B.

$40 \, \text{kg}$

C.

$50 \, \text{kg}$

D.

$60 \, \text{kg}$

Q25 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the unknown mass $m$ if all masses are in equilibrium.

A.

$50 \, \text{kg}$

B.

$60 \, \text{kg}$

C.

$70 \, \text{kg}$

D.

$80 \, \text{kg}$

Q26 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, when two bodies of mass $m_1$ and $m_2$ are attached at the ends of a string passing over a pulley (neglecting the mass of the pulley), find the acceleration $a$ of the system and the tension $T$ in the string.

A.

$a = \frac{(m_1 - m_2)g}{m_1 + m_2}, T = \frac{2 m_1 m_2}{m_1 + m_2} g$

B.

$a = \frac{(m_1 + m_2)g}{m_1 - m_2}, T = \frac{m_1 m_2}{m_1 + m_2} g$

C.

$a = \frac{(m_1 - m_2)}{(m_1 + m_2)} g, T = \frac{m_1 + m_2}{2 m_1 m_2} g$

D.

$a = \frac{2(m_1 - m_2)g}{m_1 + m_2}, T = \frac{m_1 m_2}{2(m_1 + m_2)} g$

Q27 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration of each mass if the pulley is ideal, the string is massless, and there is no friction between the pulley and the rope.

A.

$1 \, \text{m/s}^2$

B.

$2 \, \text{m/s}^2$

C.

$3 \, \text{m/s}^2$

D.

$4 \, \text{m/s}^2$

Q28 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system and the string tension $T$ for masses $6 \, \text{kg}$ and $4 \, \text{kg}$ connected over an ideal pulley.

A.

$a = 1 \, \text{m/s}^2, T = 36 \, \text{N}$

B.

$a = 2 \, \text{m/s}^2, T = 48 \, \text{N}$

C.

$a = 3 \, \text{m/s}^2, T = 42 \, \text{N}$

D.

$a = 4 \, \text{m/s}^2, T = 50 \, \text{N}$

Q29 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system and the string tension $T$ when a $4 \, \text{kg}$ block on a smooth horizontal surface is connected by a string over a pulley to a hanging $6 \, \text{kg}$ block.

A.

$a = 4 \, \text{m/s}^2, T = 24 \, \text{N}$

B.

$a = 5 \, \text{m/s}^2, T = 30 \, \text{N}$

C.

$a = 6 \, \text{m/s}^2, T = 36 \, \text{N}$

D.

$a = 8 \, \text{m/s}^2, T = 40 \, \text{N}$

Q30 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system and the string tension $T$ for a $10 \,

\text{kg}$ block on an inclined plane of $30^\circ$ connected to a hanging $20 \, \text{kg}$ block.

A.

$a = 3 \, \text{m/s}^2, T = 120 \, \text{N}$

B.

$a = 4 \, \text{m/s}^2, T = 140 \, \text{N}$

C.

$a = 5 \, \text{m/s}^2, T = 100 \, \text{N}$

D.

$a = 6 \, \text{m/s}^2, T = 80 \, \text{N}$

Q31 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system and the spring balance reading $T$ when a $3 \, \text{kg}$ block and a $2 \, \text{kg}$ block are connected over two fixed pulleys with a spring balance in between.

A.

$a = 1 \, \text{m/s}^2, T = 20 \, \text{N}$

B.

$a = 2 \, \text{m/s}^2, T = 24 \, \text{N}$

C.

$a = 3 \, \text{m/s}^2, T = 18 \, \text{N}$

D.

$a = 4 \, \text{m/s}^2, T = 22 \, \text{N}$

Q32 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system consisting of a $10 \, \text{kg}$ hanging block, a $20 \, \text{kg}$ block on a smooth table, and a $20 \, \text{kg}$ hanging block connected over two fixed pulleys.

A.

$1 \, \text{m/s}^2$

B.

$2 \, \text{m/s}^2$

C.

$3 \, \text{m/s}^2$

D.

$4 \, \text{m/s}^2$

Q33 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system and the string tension $T$ when a $3 \, \text{kg}$ hanging block and a $2 \, \text{kg}$ hanging block are connected over pulleys in an arrangement.

A.

$a = 1 \, \text{m/s}^2, T = 20 \, \text{N}$

B.

$a = 2 \, \text{m/s}^2, T = 24 \, \text{N}$

C.

$a = 3 \, \text{m/s}^2, T = 18 \, \text{N}$

D.

$a = 4 \, \text{m/s}^2, T = 22 \, \text{N}$

Q34 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system where a $4 \, \text{kg}$ block on a smooth table has an opposing force $F_0 = 20 \, \text{N}$ and is connected to a hanging $6 \, \text{kg}$ block.

A.

$a = 1 \, \text{m/s}^2$

B.

$a = 2 \, \text{m/s}^2$

C.

$a = 3 \, \text{m/s}^2$

D.

$a = 4 \, \text{m/s}^2$

Q35 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system consisting of a $20 \, \text{kg}$ hanging block, a $10 \, \text{kg}$ block on a $30^\circ$ inclined plane, and a $4 \, \text{kg}$ hanging block connected over pulleys.

A.

$a = 2.15 \, \text{m/s}^2$

B.

$a = 3.24 \, \text{m/s}^2$

C.

$a = 4.50 \, \text{m/s}^2$

D.

$a = 5.10 \, \text{m/s}^2$

Q36 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system where two $10 \, \text{kg}$ blocks are placed on opposite inclined planes of $37^\circ$ and $53^\circ$ connected by a string over a pulley at the top.

A.

$a = 1 \, \text{m/s}^2$

B.

$a = 2 \, \text{m/s}^2$

C.

$a = 3 \, \text{m/s}^2$

D.

$a = 4 \, \text{m/s}^2$

Q37 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the acceleration $a$ of the system and the string tensions $T_1$ and $T_2$ for blocks of masses $5 \, \text{kg}$, $8 \, \text{kg}$, and $2 \, \text{kg}$ on a smooth table connected to a hanging $10 \, \text{kg}$ block.

A.

$a = 2 \, \text{m/s}^2, T_1 = 10 \, \text{N}, T_2 = 26 \, \text{N}$

B.

$a = 4 \, \text{m/s}^2, T_1 = 20 \, \text{N}, T_2 = 52 \, \text{N}$

C.

$a = 5 \, \text{m/s}^2, T_1 = 25 \, \text{N}, T_2 = 65 \, \text{N}$

D.

$a = 6 \, \text{m/s}^2, T_1 = 30 \, \text{N}, T_2 = 78 \, \text{N}$

Q38 DPT Pulley and Mass Equllibrium MCQ

iCON Education HYD, 79930 92826, 73309 72826 11 Sep 2026

Concept:

From the image given below, find the time when the $6 \, \text{kg}$ block strikes the ground if it starts from rest at a height of $10 \, \text{m}$ connected to a $4 \, \text{kg}$ block on a smooth table.

A.

$t = \sqrt{\frac{5}{3}} \, \text{s}$

B.

$t = \sqrt{\frac{10}{3}} \, \text{s}$

C.

$t = \sqrt{\frac{20}{3}} \, \text{s}$

D.

$t = \sqrt{\frac{40}{3}} \, \text{s}$

Q39 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find the acceleration $a_3$ of the bottom block in the given pulley system where the acceleration of the first block is $a_1 = 4\text{ m/s}^2$ to the left and the second block is $a_2 = 6\text{ m/s}^2$ to the left.

A.

$3\text{ m/s}^2$

B.

$5\text{ m/s}^2$

C.

$4\text{ m/s}^2$

D.

$6\text{ m/s}^2$

Q40 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find $a'$ in the following string-pulley system where a block moves upwards with acceleration $a = 2\text{ m/s}^2$ on the left and another block moves downwards with acceleration $a = 8\text{ m/s}^2$ on the right.

A.

$4\text{ m/s}^2$

B.

$3\text{ m/s}^2$

C.

$5\text{ m/s}^2$

D.

$2\text{ m/s}^2$

Correct Answer: B

Explanation:

$T \times 2 + 2T a' - T \times 8 = 0$
$a' = 3$

Q41 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find the acceleration $a'$ of the block on the inclined plane in the given pulley system where the small block moves downwards with acceleration $a = 2\text{ m/s}^2$.

A.

$1\text{ m/s}^2$

B.

$2\text{ m/s}^2$

C.

$3\text{ m/s}^2$

D.

$4\text{ m/s}^2$

Q42 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find $a_2$ in the given pulley system where block 1 moves upwards with acceleration $a_1 = 4\text{ m/s}^2$ and block 2 moves downwards with acceleration $a_2$.

A.

$1\text{ m/s}^2$

B.

$2\text{ m/s}^2$

C.

$3\text{ m/s}^2$

D.

$4\text{ m/s}^2$

Q43 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find $a'$ in the given string-pulley system where the first block moves upwards with acceleration $a_1 = 2\text{ m/s}^2$, the second block moves upwards with acceleration $a_2 = 3\text{ m/s}^2$, and the third block moves downwards with acceleration $a_3 = 5\text{ m/s}^2$.

A.

$1\text{ m/s}^2$

B.

$4\text{ m/s}^2$

C.

$2\text{ m/s}^2$

D.

$3\text{ m/s}^2$

Q44 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find $a'$ in the given figure where the left block moves upwards with acceleration $a_1 = 6\text{ m/s}^2$ and the green platform moves downwards with acceleration $a'$.

A.

$4\text{ m/s}^2$

B.

$3\text{ m/s}^2$

C.

$2\text{ m/s}^2$

D.

$1\text{ m/s}^2$

Q45 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find the acceleration $a_3$ of the platform in the given string-pulley system where block 1 moves up the incline with acceleration $a_1 = 4\text{ m/s}^2$ and block 2 moves downwards with acceleration $a_2 = 6\text{ m/s}^2$.

A.

$-\frac{10}{3}\text{ m/s}^2$

B.

$-\frac{14}{3}\text{ m/s}^2$

C.

$-\frac{12}{3}\text{ m/s}^2$

D.

$-\frac{8}{3}\text{ m/s}^2$

Correct Answer: B

Explanation:

$4 \times 2 + 6 \times 1 + 3 \times a_3 = 0$
$a_3 = -\frac{14}{3}$ ('-' sign means downward acceleration)

Q46 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find $a_2$ in the given system where block 1 moves horizontally to the right with acceleration $a_1 = 10\text{ m/s}^2$ and tension $T$ makes an angle of $37^\circ$ with the horizontal.

A.

$6\text{ m/s}^2$

B.

$8\text{ m/s}^2$

C.

$10\text{ m/s}^2$

D.

$5\text{ m/s}^2$

Q47 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find $a_2$ in the given system where a ring slides along a horizontal rod with acceleration $a_1 = 10\text{ m/s}^2$ and the string attached to it makes an angle of $37^\circ$ with the rod.

A.

$6\text{ m/s}^2$

B.

$10\text{ m/s}^2$

C.

$8\text{ m/s}^2$

D.

$4\text{ m/s}^2$

Q48 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

In the figure, find the velocity of block B, if velocity of A is $V_0$ in downward direction?

A.

$\frac{V_0}{\cos \theta}$

B.

$\frac{V_0}{1 + \cos \theta}$

C.

$V_0 (1 + \cos \theta)$

D.

$\frac{V_0}{\sin \theta}$

Correct Answer: B

Explanation:

$-T V_0 + T v_B + T v_B \cos \theta = 0$
$T V_0 = T v_B (1 + \cos \theta)$
$v_B = \frac{V_0}{1 + \cos \theta}$

Q49 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find $a_3$ in the given string-pulley system where the first block moves upwards with acceleration $a_1 = 2\text{ m/s}^2$, the second block moves upwards with acceleration $a_2 = 4\text{ m/s}^2$, and the third block has acceleration $a_3$.

A.

$-2\text{ m/s}^2$

B.

$-6\text{ m/s}^2$

C.

$-4\text{ m/s}^2$

D.

$-3\text{ m/s}^2$

Q50 DPT Pulley & mass Acceleration MCQ

iCON Education HYD, 79930 92826, 73309 72826 16 Sep 2026

Concept:

Find the acceleration $a'$ of the block on the horizontal surface in the given pulley system where the bottom platform moves downwards with acceleration $a = 6\text{ m/s}^2$.

A.

$12\text{ m/s}^2$

B.

$16\text{ m/s}^2$

C.

$18\text{ m/s}^2$

D.

$24\text{ m/s}^2$

Physics-I Chapters

Newton's Laws of Motion

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