Chemical Bonding & Molecular Structure
256 Questions
2021
JEE Mains
Numerical
JEE Main 2021 (Online) 18th March Evening Shift
The number of species below that have two lone pairs of electrons in their central atom is _________. (Round off to the Nearest Integer).
SF4, BF$_4^ - $, ClF3, AsF3, PCl5, BrF5, XeF4, SF6
SF4, BF$_4^ - $, ClF3, AsF3, PCl5, BrF5, XeF4, SF6
Correct Answer: 2
Explanation:
2021
JEE Mains
Numerical
JEE Main 2021 (Online) 18th March Morning Shift
AX is a covalent diatomic molecule where A and X are second row elements of periodic table. Based on Molecular orbital theory, the bond order of AX is 2.5. The total number of electrons in AX is __________. (Round off to the Nearest Integer).
Correct Answer: 15
Explanation:
The compound AX is NO its bond order is 2.5 and it has total 15 electrons.
Note : Total number of electrons equal to 13 will also have the 2.5 bond order. But in this case neutral diatomic molecule will not be possible.
Note : Total number of electrons equal to 13 will also have the 2.5 bond order. But in this case neutral diatomic molecule will not be possible.
2021
JEE Mains
Numerical
JEE Main 2021 (Online) 25th February Morning Shift
Among the following, the number of halide(s) which is/are inert to hydrolysis is _________.
(A) BF3
(B) SiCl4
(C) PCl5
(D) SF6
(A) BF3
(B) SiCl4
(C) PCl5
(D) SF6
Correct Answer: 1
Explanation:
BF3 – Shows Partial hydrolysis
SiCl4 – Undergoes hydrolysis readily
PCl5 – Undergoes hydrolysis by addition– elimination mechanism.
SF6 – Due to crowding Inert towards hydrolysis.
SiCl4 – Undergoes hydrolysis readily
PCl5 – Undergoes hydrolysis by addition– elimination mechanism.
SF6 – Due to crowding Inert towards hydrolysis.
2020
JEE Mains
Numerical
JEE Main 2020 (Online) 6th September Morning Slot
The number of Cl = O bonds in perchloric acid
is, "________".
Correct Answer: 3
Explanation:
The structure of perchloric acid is
The number Cl = O bonds in HClO4 is 3.
The number Cl = O bonds in HClO4 is 3.
2020
JEE Mains
Numerical
JEE Main 2020 (Online) 7th January Morning Slot
Chlorine reacts with hot and concentrated NaOH and produces compounds (X) and (Y). Compound
(X) gives white precipitate with silver nitrate solution. The average bond order between CI and O
atoms in (Y) is.
Correct Answer: 1.66to1.67
Explanation:
3Cl2 + 6NaOH $ \to $ 5NaCl + NaClO3 + 3H2O
NaCl + AgNO3 $ \to $ AgCl- $ \downarrow $ + NaNO3
$ \therefore $ X = NaCl then Y = NaClO3
Here in anion ClO3- has bond between Cl and O atom.
Bond order of Cl–O Bond =
= ${5 \over 3}$ = 1.67
NaCl + AgNO3 $ \to $ AgCl- $ \downarrow $ + NaNO3
$ \therefore $ X = NaCl then Y = NaClO3
Here in anion ClO3- has bond between Cl and O atom.
Bond order of Cl–O Bond =
Total bond
Total resonating structure
.
= ${5 \over 3}$ = 1.67
2013
JEE Mains
MSQ
JEE Main 2013 (Offline)
Which one of the following molecules is expected to exhibit diamagnetic behaviour?
A.
N2
B.
O2
C.
S2
D.
C2