Circle
101 Questions
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1978
Q101
JEE Advanced
Numerical
14 Mar 2026
Find the equation of the circle whose radius is 5 and which touches the circle ${x^2}\, + \,{y^2}\, - \,2x\,\, - 4y\, - 20 = 0\,$ at the point (5, 5).
Correct Answer: $${x^2}\, + \,{y^2}\, - \,18x\,\, - 16y\, + 120 = 0\,$$