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Motion in 1D

87 Questions Start Objective Physics Vol-1 Test
All Exams Objective Physics Vol-1 DPT
Q1 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Distance is the total length of the path covered by an object during its motion, regardless of the direction of travel. It is a scalar quantity and is calculated by adding the individual path lengths traversed in each step of the journey.
A scooter is moving along a straight line $AB$ covers a distance of $360\text{ m}$ in $24\text{ s}$ and returns back from $B$ to $C$ and covers $240\text{ m}$ in $18\text{ s}$. Find the total distance travelled by the scooter.
A.
$120\text{ m}$
B.
$600\text{ m}$
C.
$360\text{ m}$
D.
$240\text{ m}$
Q2 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: When a circular wheel rolls without slipping, the total distance covered in $n$ revolutions is equal to $n$ times the circumference of the wheel. The circumference of a circle is given by $\pi d$, where $d$ is the diameter of the wheel.
A wheel completes $2000\text{ revolutions}$ to cover the $9.5\text{ km}$ distance. Find the diameter of the wheel.
A.
$1.51\text{ m}$
B.
$3.02\text{ m}$
C.
$0.75\text{ m}$
D.
$2.14\text{ m}$
Q3 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Distance is the total path length traversed by a body, regardless of direction. Displacement is the shortest straight-line distance vector from the initial position to the final position, which can be evaluated using vector addition or right-angled triangle geometry (Pythagoras theorem).
A man starts from his home and walks $50\text{ m}$ towards north, then he turns towards east and walks $40\text{ m}$ and then reaches to his office after moving $20\text{ m}$ towards south. What is the total distance covered by the man from his home to office and what is his displacement from his home to office?
A.
Distance = $110\text{ m}$, Displacement = $50\text{ m}$
B.
Distance = $50\text{ m}$, Displacement = $110\text{ m}$
C.
Distance = $110\text{ m}$, Displacement = $70\text{ m}$
D.
Distance = $70\text{ m}$, Displacement = $50\text{ m}$
Q4 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Distance is the actual length of the path traversed by an object, while displacement is the shortest straight-line distance from its initial position to its final position. For motion along a circular path, distance is calculated as a fraction of the circle's circumference, and displacement is calculated using the straight-line chord length connecting the initial and final positions.
An object covers $1/4\text{th}$ of a circular path of radius $r$. What will be the ratio of the distance and displacement of the object?
A.
$\frac{\pi}{2\sqrt{2}}$
B.
$\frac{\pi}{\sqrt{2}}$
C.
$\frac{2\sqrt{2}}{\pi}$
D.
$\frac{\pi}{4}$
Q5 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: For motion along a semicircular path, the displacement between the initial and final points is equal to the diameter of the path ($2r$). The distance travelled is the actual path length along the semicircle, which is equal to half of the circumference ($\pi r$).
Displacement of a person moving from $X$ to $Y$ along a semicircular path of radius $r$ is $200\text{ m}$. What is the distance travelled by him?
A.
$200\text{ m}$
B.
$100\pi\text{ m}$
C.
$400\text{ m}$
D.
$200\pi\text{ m}$
Q6 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Distance is the total actual path length covered during motion, which for circular motion depends on the number of completed revolutions multiplied by the circumference ($2\pi r$ or $\pi D$). Displacement is the shortest distance between the initial position and the final position. For an integer number of full rounds, displacement is zero, while for a half round, displacement is equal to the diameter of the track.
An athlete completes one round of a circular track of diameter $200\text{ m}$ in $40\text{ s}$. What will be the distance covered and the displacement at the end of $2\text{ min } 20\text{ s}$?
A.
Distance = $2200\text{ m}$, Displacement = $200\text{ m}$
B.
Distance = $200\text{ m}$, Displacement = $2200\text{ m}$
C.
Distance = $4400\text{ m}$, Displacement = $100\text{ m}$
D.
Distance = $2200\text{ m}$, Displacement = $0\text{ m}$
Q7 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: One-dimensional motion is the motion of a body along a straight line path. In such motion, only one coordinate is required to specify the position of the object at any instant of time.
Which of the following is a one-dimensional motion?
A.
Landing of an aircraft
B.
Earth revolving around the sun
C.
Motion of wheels of moving train
D.
Train running on a straight track
Q8 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: The distance of a point from the origin (or starting point) in three-dimensional space is given by the magnitude of the displacement vector. When an object moves along three mutually perpendicular directions (X, Y, and Z axes), the net direct distance from the initial position is calculated using the 3D distance formula: $d = \sqrt{x^2 + y^2 + z^2}$.
A person moves towards east for $3\text{ m}$, then towards north for $4\text{ m}$ and then moves upwards for $5\text{ m}$. What is his distance now from the starting point?
A.
$10\text{ m}$
B.
$12\text{ m}$
C.
$5\sqrt{2}\text{ m}$
D.
$5\text{ m}$
Q9 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Distance along a circular arc is equal to the product of the radius of the circle and the angle subtended by the arc at the center measured in radians ($\text{Distance} = R \times \theta$). To convert an angle from degrees to radians, multiply by $\frac{\pi}{180^{\circ}}$.
A particle moves in a circle of radius $R$ from $A$ to $B$ as shown in figure. The distance covered by the object is image.png
A.
$\frac{\pi R}{3}$
B.
$\frac{\pi R}{2}$
C.
$\frac{\pi R}{4}$
D.
$\pi R$
Q10 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: When a wheel rolls forward by half a revolution without slipping, its center moves horizontally by a distance equal to half of its circumference ($\pi R$). Simultaneously, the point initially in contact with the ground moves from the bottom position to the top position of the wheel, resulting in a vertical displacement equal to the diameter of the wheel ($2R$). The net displacement magnitude is the straight-line distance calculated using the Pythagorean theorem: $d = \sqrt{(\pi R)^2 + (2R)^2}$.
A wheel of radius $1\text{ m}$ rolls forward half a revolution on a horizontal ground. The magnitude of displacement of the point of the wheel initially in contact with the ground is
A.
$2\pi$
B.
$\sqrt{2}\pi$
C.
$\sqrt{\pi^2 + 4}$
D.
$\pi$
Q11 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Displacement ($\Delta x$) on a straight line is defined as the final position ($x_f$) minus the initial position ($x_i$), given by $\Delta x = x_f - x_i$. Displacement is negative when the final position lies to the left of the initial position ($x_f < x_i$).
The three initial and final positions of a man on the x-axis are given as:
(i) $(-8\text{ m}, 7\text{ m})$
(ii) $(7\text{ m}, -3\text{ m})$
(iii) $(-7\text{ m}, 3\text{ m})$
Which pair gives the negative displacement?
A.
(i)
B.
(ii)
C.
(iii)
D.
(i) and (iii)
Q12 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Displacement is the shortest straight-line distance between the initial and final positions of an object, while distance is the total length of the actual path traversed. Since displacement cannot exceed the total path length, displacement is always less than or equal to distance. Therefore, the ratio of displacement to distance is always less than or equal to one (equal to one for unidirectional motion in a straight line).
The numerical ratio of displacement to the distance for a moving object is always
A.
less than one
B.
equal to one
C.
equal to or less than one
D.
equal to or greater than one
Q13 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Distance is the actual length of the path traversed by a particle, which for half a revolution of a circular path is equal to half of the circumference ($\pi r$). Displacement is the shortest straight-line distance from the initial position to the final position, which for a half revolution is equal to the diameter of the circular path ($2r$).
A particle moves along a circular path of radius $r$. The distance and displacement of the particle after half a revolution is
A.
$0, 2\pi r$
B.
$2\pi r, 0$
C.
$0, \pi r$
D.
$\pi r, 0$
Q14 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Distance (total path length covered) and Displacement (shortest distance between initial and final position, i.e., final position minus initial position).
A particle starts from the origin, goes along $X$-axis to the point $(20\text{ m}, 0)$ and then returns along the same line to the point $(-20\text{ m}, 0)$. The distance and displacement of the particle during the trip are
A.
$40\text{ m}, 0$
B.
$40\text{ m}, -20\text{ m}$
C.
$60\text{ m}, -20\text{ m}$
D.
$40\text{ m}, 20\text{ m}$
Q15 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average speed, defined as the total distance traveled divided by the total time taken.
Abdul while driving to school computes the average speed for his trip to be $20\text{ km h}^{-1}$. On his return trip along the same route, there is less traffic and the average speed is $40\text{ km h}^{-1}$. What is the average speed for Abdul's trip?
A.
$30.5\text{ km h}^{-1}$
B.
$26.67\text{ km h}^{-1}$
C.
$24.5\text{ km h}^{-1}$
D.
$32.0\text{ km h}^{-1}$
Q16 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average speed when the distance is split into equal halves travelled at different constant speeds, calculated using the harmonic mean of the speeds.
A car covers the first half of the distance between two places at a speed of $40\text{ km h}^{-1}$ and second half at $60\text{ km h}^{-1}$. Calculate the average speed of the car.
A.
$52\text{ km h}^{-1}$
B.
$45\text{ km h}^{-1}$
C.
$48\text{ km h}^{-1}$
D.
$50\text{ km h}^{-1}$
Q17 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average speed for a round trip with two different speeds over equal distances, calculated as the harmonic mean of the speeds.
A car moves from $X$ to $Y$ with a uniform speed $v_u$ and returns to $X$ with a uniform speed $v_d$. Find average speed for this round trip.
A.
$\frac{v_u v_d}{v_u + v_d}$
B.
$\frac{3v_u v_d}{v_u + v_d}$
C.
$\frac{2v_u v_d}{v_u + v_d}$
D.
$\frac{v_u + v_d}{2v_u v_d}$
Q18 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average speed, defined as the total distance traveled divided by the total time taken for a journey with varying segments of speed and time.
A particle travelled half the distance with a speed $v_0$. The remaining part of the distance was covered with speed $v_1$ for half the time and with speed $v_2$ for the other half of the time. Find the average speed of the particle.
A.
$\frac{2v_0(v_1 + v_2)}{v_1 + v_2 + v_0}$
B.
$\frac{2v_0(v_1 + v_2)}{v_1 + v_2 + 2v_0}$
C.
$\frac{v_0(v_1 + v_2)}{2(v_1 + v_2 + v_0)}$
D.
$\frac{v_0(v_1 + v_2)}{v_1 + v_2 + v_0}$
Q19 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average velocity, defined as the ratio of total displacement to the total time taken for the motion.
In one second, a particle goes from point $A$ to point $B$ moving in a semicircular path as shown in figure. Find the magnitude of average velocity. image.png
A.
$1.5\text{ ms}^{-1}$
B.
$2.5\text{ ms}^{-1}$
C.
$2\text{ ms}^{-1}$
D.
$3\text{ ms}^{-1}$
Q20 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Distance as total path length ($AB + BC + CD$) and Displacement as the shortest straight-line distance from initial to final position using vector components.
A farmer has to go $500\text{ m}$ due north, $400\text{ m}$ due east and $200\text{ m}$ due south to reach his field. If he takes $20\text{ min}$ to reach the field, (i) what distance has he to walk to reach the field? (ii) what is the displacement from his house to the field? (iii) what is the average speed of farmer during the walk? (iv) what is the average velocity of farmer during the walk? [Note: This question specifically focuses on finding the total distance and magnitude of displacement.]
A.
Distance: $1100\text{ m}$, Displacement: $500\text{ m}$
B.
Distance: $1000\text{ m}$, Displacement: $400\text{ m}$
C.
Distance: $1100\text{ m}$, Displacement: $600\text{ m}$
D.
Distance: $900\text{ m}$, Displacement: $500\text{ m}$
Q21 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average speed defined as total distance divided by total time, and average velocity defined as net displacement divided by total time.
Joseph jogs from one end $A$ to the other end $B$ of a straight $300\text{ m}$ road in $2\text{ min } 50\text{ s}$ and then turns around and jogs $100\text{ m}$ back to point $C$ in another $1\text{ min}$. What are Joseph's average speeds and velocities in jogging (i) from $A$ to $B$ and (ii) from $A$ to $C$?
A.
Average speed from $A$ to $B$ is $1.76\text{ ms}^{-1}$, average velocity from $A$ to $B$ is $1.76\text{ ms}^{-1}$; Average speed from $A$ to $C$ is $1.74\text{ ms}^{-1}$, average velocity from $A$ to $C$ is $0.87\text{ ms}^{-1}$
B.
Average speed from $A$ to $B$ is $1.50\text{ ms}^{-1}$, average velocity from $A$ to $B$ is $1.50\text{ ms}^{-1}$; Average speed from $A$ to $C$ is $1.20\text{ ms}^{-1}$, average velocity from $A$ to $C$ is $0.50\text{ ms}^{-1}$
C.
Average speed from $A$ to $B$ is $2.00\text{ ms}^{-1}$, average velocity from $A$ to $B$ is $2.00\text{ ms}^{-1}$; Average speed from $A$ to $C$ is $1.90\text{ ms}^{-1}$, average velocity from $A$ to $C$ is $1.10\text{ ms}^{-1}$
D.
Average speed from $A$ to $B$ is $1.76\text{ ms}^{-1}$, average velocity from $A$ to $B$ is $1.76\text{ ms}^{-1}$; Average speed from $A$ to $C$ is $2.10\text{ ms}^{-1}$, average velocity from $A$ to $C$ is $1.50\text{ ms}^{-1}$
Q22 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Finding instantaneous position from a given position-time equation, calculating displacement as the difference between final and initial positions, and average velocity as displacement divided by the time interval.
The position of an object moving along $X$-axis is given by $x = 3t - 4t^2 + t^3$, where $x$ is in metres and $t$ in seconds. Find the position of the object at $t = 2\text{ s}$ and $t = 4\text{ s}$. What is the object displacement between $t = 0\text{ s}$ and $t = 4\text{ s}$, and what is its average velocity for the time interval from $t = 2\text{ s}$ to $t = 4\text{ s}$?
A.
$x_2 = -2\text{ m}$, $x_4 = 12\text{ m}$, Displacement = $12\text{ m}$, Average Velocity = $7\text{ ms}^{-1}$
B.
$x_2 = 2\text{ m}$, $x_4 = 10\text{ m}$, Displacement = $10\text{ m}$, Average Velocity = $5\text{ ms}^{-1}$
C.
$x_2 = -4\text{ m}$, $x_4 = 14\text{ m}$, Displacement = $14\text{ m}$, Average Velocity = $8\text{ ms}^{-1}$
D.
$x_2 = -2\text{ m}$, $x_4 = 15\text{ m}$, Displacement = $15\text{ m}$, Average Velocity = $9\text{ ms}^{-1}$
Q23 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average speed for a journey when time is divided into equal intervals with different constant speeds, calculated as the arithmetic mean of the speeds.
A car has to cover the distance $60\text{ km}$. If half of the total time, it travels with speed $80\text{ km h}^{-1}$ and in rest half time, its speed becomes $40\text{ km h}^{-1}$, the average speed of car will be
A.
$120\text{ km h}^{-1}$
B.
$80\text{ km h}^{-1}$
C.
$60\text{ km h}^{-1}$
D.
$180\text{ km h}^{-1}$
Q24 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average speed, defined as the total distance traveled divided by the total time taken for the trip.
During the first $18\text{ min}$ of a $60\text{ min}$ trip, a car has an average speed of $11\text{ m min}^{-1}$. What should be the average speed for remaining $42\text{ min}$, so that car is having an average speed of $21\text{ m min}^{-1}$ for the entire trip?
A.
$25.3\text{ m min}^{-1}$
B.
$29.2\text{ m min}^{-1}$
C.
$31\text{ m min}^{-1}$
D.
$35.6\text{ m min}^{-1}$
Q25 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average speed, defined as the total distance traveled divided by the total time taken for the specified time interval.
A man walks on a straight road from his home to a market $2.5\text{ km}$ away with a speed of $5\text{ km h}^{-1}$. Finding the market closed, he instantly turns and walks back home with a speed of $7.5\text{ km h}^{-1}$. The average speed of the man over the interval of time $0$ to $40\text{ min}$ is equal to
A.
$5\text{ km h}^{-1}$
B.
$\frac{25}{4}\text{ km h}^{-1}$
C.
$\frac{30}{4}\text{ km h}^{-1}$
D.
$\frac{45}{8}\text{ km h}^{-1}$
Q26 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Distance, displacement, average speed, and average velocity definitions for linear motion.
A particle is constrained to move on a straight line path. It returns to the starting point after $10\text{ s}$. The total distance covered by the particle during this time is $30\text{ m}$. Which of the following statements about the motion of the particle is true?
A.
Displacement of the particle is zero
B.
Average speed of the particle is $3\text{ ms}^{-1}$
C.
Displacement of the particle is $30\text{ m}$
D.
Both (a) and (b)
Q27 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Uniform speed and distance travelled. The total distance covered by a train to completely cross a bridge is the sum of the length of the train and the length of the bridge.
A $150\text{ m}$ long train is moving with a uniform velocity of $45\text{ km h}^{-1}$. The time taken by the train to cross a bridge of length $850\text{ m}$ is
A.
$56\text{ s}$
B.
$68\text{ s}$
C.
$80\text{ s}$
D.
$92\text{ s}$
Q28 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average velocity, defined as total displacement divided by total time taken.
An insect crawls a distance of $4\text{ m}$ along north in $10\text{ s}$ and then a distance of $3\text{ m}$ along east in $5\text{ s}$. The average velocity of the insect is
A.
$\frac{7}{15}\text{ ms}^{-1}$
B.
$\frac{1}{5}\text{ ms}^{-1}$
C.
$\frac{1}{3}\text{ ms}^{-1}$
D.
$\frac{4}{5}\text{ ms}^{-1}$
Q29 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average velocity defined as the total displacement divided by the total time taken.
A particle traversed $\frac{3}{4}\text{th}$ of the circle of radius $R$ in time $t$. The magnitude of the average velocity of the particle in this time interval is
A.
$\frac{\pi R}{t}$
B.
$\frac{3\pi R}{2t}$
C.
$\frac{R\sqrt{2}}{t}$
D.
$\frac{R}{\sqrt{2}t}$
Q30 Objective Physics Vol-1 Basic Concepts of Motion MCQ
24 Jul 2026
Concept: Kinematics - Average velocity along a semicircular path, defined as the displacement (diameter of the semicircle) divided by the time taken to cover the semicircular arc.
A boy is running over a circular track with uniform speed of $10\text{ ms}^{-1}$. What is the average velocity for movement of boy along semicircle (in $\text{ms}^{-1}$)?
A.
$\frac{10}{\pi}$
B.
$\frac{40}{\pi}$
C.
$10$
D.
$\frac{20}{\pi}$
Q31 Objective Physics Vol-1 Basic Concepts of Motion MCQ
27 Jul 2026
Concept: Kinematic equations for uniformly accelerated motion
A car starts from rest, attains a velocity of $18 \mathrm{kmh}^{-1}$ with an acceleration of $0.5 \mathrm{ms}^{-2}$, travels 4 km with this uniform velocity and then comes to halt with a uniform deceleration of $0.4 \mathrm{ms}^{-2}$. Calculate the total time of travel of the car.
A.
812.5 s
B.
802.5 s
C.
822.5 s
D.
832.5 s
Q32 Objective Physics Vol-1 Basic Concepts of Motion MCQ
27 Jul 2026
Concept: Vector nature of acceleration and its dependence on velocity
Acceleration of a particle changes when
A.
direction of velocity changes
B.
magnitude of velocity changes
C.
Both (a) and (b)
D.
speed changes
Q33 Objective Physics Vol-1 Basic Concepts of Motion MCQ
27 Jul 2026
Concept: Relationship between acceleration, velocity, and speed
If a particle moves with an acceleration, then which of the following can remain constant?
A.
Both speed and velocity
B.
Neither speed nor velocity
C.
Only the velocity
D.
Only the speed
Q34 Objective Physics Vol-1 Basic Concepts of Motion MCQ
27 Jul 2026
Concept: Kinematic equations relating average velocity, distance, time, and acceleration
The average velocity of a body moving with uniform acceleration travelling a distance of $3.06 \mathrm{m}$ is $0.34 \mathrm{ms}^{-1}$. If the change in velocity of the body is $0.18 \mathrm{ms}^{-1}$, then during this time, its uniform acceleration is
A.
$0.01 \mathrm{ms}^{-2}$
B.
$0.02 \mathrm{ms}^{-2}$
C.
$0.03 \mathrm{ms}^{-2}$
D.
$0.04 \mathrm{ms}^{-2}$
Q35 Objective Physics Vol-1 Basic Concepts of Motion MCQ
27 Jul 2026
Concept: Calculation of retardation using the first equation of motion
A car travelling with a velocity of $80 \mathrm{km/h}$ slowed down to $44 \mathrm{km/h}$ in $15 \mathrm{s}$. The retardation is
A.
$0.67 \mathrm{ms}^{-2}$
B.
$1 \mathrm{ms}^{-2}$
C.
$1.25 \mathrm{ms}^{-2}$
D.
$1.5 \mathrm{ms}^{-2}$
Q36 Objective Physics Vol-1 Basic Concepts of Motion MCQ
27 Jul 2026
Concept: Acceleration in straight-line motion versus curved-path motion at constant speed
An object is moving along the path OABO with constant speed, then image.png
A.
the acceleration of the object while moving along the path OABO is zero
B.
the acceleration of the object along the path OA and BO is zero
C.
there must be some acceleration along the path AB
D.
Both (b) and (c)
Q37 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Kinematic equations for uniformly accelerated motion
Two cars start off a race with velocities $2 \mathrm{ms}^{-1}$ and $4 \mathrm{ms}^{-1}$ and travel in a straight line with uniform accelerations $2 \mathrm{ms}^{-2}$ and $1 \mathrm{ms}^{-2}$, respectively. What is the length of the path, if they reach the final point at the same time?
A.
12 m
B.
24 m
C.
36 m
D.
48 m
Q38 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Third equation of motion and calculation of retardation
A car was moving at a rate of $18 \mathrm{kmh}^{-1}$. When the brakes were applied, it comes to rest at a distance of 100 m. Calculate the retardation produced by the brakes.
A.
$0.125 \mathrm{ms}^{-2}$
B.
$0.250 \mathrm{ms}^{-2}$
C.
$0.500 \mathrm{ms}^{-2}$
D.
$1.000 \mathrm{ms}^{-2}$
Q39 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Stopping distance using the third equation of motion
Two cars are travelling towards each other on a straight road at velocities $10 \mathrm{ms}^{-1}$ and $12 \mathrm{ms}^{-1}$, respectively. When they are 150 m apart, both the drivers apply their brakes and each car decelerates at $2 \mathrm{ms}^{-2}$ until it stops. How far apart will they be when both of them come to rest?
A.
61 m
B.
75 m
C.
89 m
D.
100 m
Q40 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Relative motion and time of flight for constant velocity
A train travelling at $20 \mathrm{kmh}^{-1}$ is approaching a platform. A bird is sitting on a pole on the platform. When the train is at a distance of 2 km from the pole, brakes are applied which produce a uniform deceleration in it. At that instant, the bird flies towards the train at $60 \mathrm{kmh}^{-1}$ and after touching the nearest point on the train flies back to the pole and then flies towards the train and continues repeating itself. Calculate how much distance the bird covers before the train stops?
A.
6 km
B.
12 km
C.
18 km
D.
24 km
Q41 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Kinematic equations for uniformly accelerated motion applied in segments
A particle starts with an initial velocity and passes successively over the two halves of a given distance with accelerations $a_1$ and $a_2$, respectively. The final velocity is the same as if the whole distance is covered with a uniform acceleration of
A.
$\frac{a_1 - a_2}{2}$
B.
$\frac{2a_1 a_2}{a_1 + a_2}$
C.
$\frac{a_1 + a_2}{2}$
D.
$\sqrt{a_1 a_2}$
Q42 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Equations of motion for two bodies starting from rest
In a car race, car A takes a time $t$ less than car B at the finish point and passes the finishing point with speed $v$ more than that of the car B. Assuming that both the cars start from rest and travel with constant accelerations $a_1$ and $a_2$ respectively, the correct relation is
A.
$v = \sqrt{a_1 a_2}t$
B.
$v = (a_1 + a_2)t$
C.
$v = \sqrt{\frac{a_1}{a_2}}t$
D.
$v = \frac{a_1 a_2}{t}$
Q43 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Distance travelled in the nth second of uniformly accelerated motion
A body starting from rest has an acceleration of $4 \mathrm{ms}^{-2}$. The distance travelled by it in the 5th second is
A.
20 m
B.
18 m
C.
16 m
D.
24 m
Q44 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Ratio of displacements in successive time intervals for a body starting from rest
A particle starts from rest and moves under constant acceleration in a straight line. The ratio of displacements in successive seconds is
A.
1:2:3:...
B.
1:4:9:...
C.
2:4:6:...
D.
1:3:5:...
Q45 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: First equation of motion for uniformly accelerated motion
Velocity of a body moving along a straight line with uniform acceleration reduces by $\frac{3}{4}$ of its initial velocity in time $t_{0}$. The total time of motion of the body till its velocity becomes zero is
A.
$\frac{4}{3}t_{0}$
B.
$\frac{3}{2}t_{0}$
C.
$\frac{5}{3}t_{0}$
D.
$\frac{8}{3}t_{0}$
Q46 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Second equation of motion for displacement
The displacement of a body in 8 s starting from rest with an acceleration of $20 \mathrm{cms}^{-2}$ is
A.
$64 \mathrm{m}$
B.
$64 \mathrm{cm}$
C.
$640 \mathrm{cm}$
D.
$0.064 \mathrm{m}$
Q47 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Integration of velocity to find displacement and distance
The motion of a particle is described by the equation $v = at$. The distance travelled by the particle in the first 4 s is
A.
$4a$
B.
$12a$
C.
$6a$
D.
$8a$
Q48 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Second equation of motion for calculating time
A particle starts with a velocity of $2 \mathrm{ms}^{-1}$ and moves in a straight line with a retardation of $0.1 \mathrm{ms}^{-2}$. The first time at which the particle is 15 m from the starting point is
A.
10 s
B.
20 s
C.
30 s
D.
40 s
Q49 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Calculation of total distance in different phases of motion
A particle starts from rest, accelerates at $2 \mathrm{ms}^{-2}$ for 10 s and then moves with constant speed of $20 \mathrm{ms}^{-1}$ for 30 s and then decelerates at $4 \mathrm{ms}^{-2}$ till it stops after next 5 s. What is the distance travelled by it?
A.
750 m
B.
800 m
C.
700 m
D.
850 m
Q50 Objective Physics Vol-1 Uniform Accelerated MCQ
27 Jul 2026
Concept: Equation of motion for uniform velocity and uniform acceleration
A body is moving with uniform velocity of $8 \mathrm{ms}^{-1}$. When the body just crossed another body, the second one starts and moves with uniform acceleration of $4 \mathrm{ms}^{-2}$. The time after which two bodies meet, will be
A.
2 s
B.
4 s
C.
6 s
D.
8 s