Q51
DPT
5. Relative Motion
MCQ
27 Aug 2026
Concept:
A.
$4\text{ sec}$
B.
$2\text{ sec}$
C.
$3\text{ sec}$
D.
$1\text{ sec}$
Q52
DPT
5. Relative Motion
MCQ
27 Aug 2026
Concept:
A.
$3\text{ sec}$
B.
$4\text{ sec}$
C.
$2\text{ sec}$
D.
$5\text{ sec}$
Q53
DPT
5. Relative Motion
MCQ
27 Aug 2026
Concept:
A.
$3\text{ sec}$
B.
$4\text{ sec}$
C.
$5\text{ sec}$
D.
$2\text{ sec}$
Q54
DPT
5. Relative Motion
MCQ
27 Aug 2026
Concept:
A.
$3\text{ sec}$
B.
$5\text{ sec}$
C.
$4\text{ sec}$
D.
$2\text{ sec}$
Q55
DPT
5. Relative Motion
MCQ
27 Aug 2026
Concept:
A.
$3\text{ sec}$
B.
$5\text{ sec}$
C.
$4\text{ sec}$
D.
$2\text{ sec}$
Q56
DPT
5. Relative Motion
MCQ
29 Aug 2026
Concept:
A.
$10\text{ km/hr}$
B.
$8\text{ km/hr}$
C.
$6\text{ km/hr}$
D.
$4\text{ km/hr}$
Q57
DPT
5. Relative Motion
MCQ
29 Aug 2026
Concept:
A.
$-6\hat{i} - 8\hat{j}$
B.
$6\hat{i} + 8\hat{j}$
C.
$8\hat{i}$
D.
$6\hat{i}$
Q58
DPT
5. Relative Motion
MCQ
29 Aug 2026
Concept:
A.
$1\text{ m/s}$
B.
$2\text{ m/s}$
C.
$3\text{ m/s}$
D.
$4\text{ m/s}$
Q59
DPT
5. Relative Motion
MCQ
29 Aug 2026
Concept:
A.
$30^\circ$ with downstream
B.
$60^\circ$ with downstream
C.
$120^\circ$ with downstream
D.
South
Q60
DPT
5. Relative Motion
MCQ
29 Aug 2026
Concept:
A.
$30^\circ$ against the current from normal to the direction of flow
B.
$45^\circ$ against the current from normal to the direction of flow
C.
$60^\circ$ against the current from normal to the direction of flow
D.
$90^\circ$ against the current from normal to the direction of flow
Q61
DPT
5. Relative Motion
MCQ
29 Aug 2026
Concept:
Calculate the time taken by the man to cross the river at right angles to the flow; if the width of the river is $\sqrt{3}\text{ km}$.
A.
$10\text{ minutes}$
B.
$20\text{ minutes}$
C.
$30\text{ minutes}$
D.
$40\text{ minutes}$
Q62
DPT
MCQ
29 Aug 2026
```python
# Let's verify the problem statement and calculations from the image.
# The question in the image (inside the highlighted area - AoI) is:
# "Q. A river is flowing with velocity $5\text{ m/s}$ wrt ground. A man can swim with velocity $10\text{ m/s}$ wrt river. The width of the river is $100\text{ m}$.
# (1) In which direction man should swim so that he crosses that river in min distance travel also find time taken to cross the river."
# Wait, let's check the solution in the image:
# v_{m/r} = v = 10 m/s
# u = 5 m/s
# d = 100 m
# v \sin\theta = u => 10 \sin\theta = 5 => \sin\theta = 1/2 => \theta = 30^\circ
# Let's write code to verify the calculation.
v = 10
u = 5
d = 100
import math
theta_deg = math.degrees(math.asin(u / v))
print(f"theta: {theta_deg}")
# Minimum distance to cross is width d = 100 m.
# Time taken: t = d / (v * cos(theta))
theta_rad = math.radians(theta_deg)
t = d / (v * math.cos(theta_rad))
print(f"time: {t}")
```
```text
theta: 30.000000000000004
time: 11.547005383792516
```
# Let's verify the problem statement and calculations from the image.
# The question in the image (inside the highlighted area - AoI) is:
# "Q. A river is flowing with velocity $5\text{ m/s}$ wrt ground. A man can swim with velocity $10\text{ m/s}$ wrt river. The width of the river is $100\text{ m}$.
# (1) In which direction man should swim so that he crosses that river in min distance travel also find time taken to cross the river."
# Wait, let's check the solution in the image:
# v_{m/r} = v = 10 m/s
# u = 5 m/s
# d = 100 m
# v \sin\theta = u => 10 \sin\theta = 5 => \sin\theta = 1/2 => \theta = 30^\circ
# Let's write code to verify the calculation.
v = 10
u = 5
d = 100
import math
theta_deg = math.degrees(math.asin(u / v))
print(f"theta: {theta_deg}")
# Minimum distance to cross is width d = 100 m.
# Time taken: t = d / (v * cos(theta))
theta_rad = math.radians(theta_deg)
t = d / (v * math.cos(theta_rad))
print(f"time: {t}")
```
```text
theta: 30.000000000000004
time: 11.547005383792516
```
Correct Answer:
Q63
DPT
MCQ
29 Aug 2026
Concept:
A.
$30^\circ$ upstream, $11.55\text{ s}$
B.
$30^\circ$ downstream, $10\text{ s}$
C.
$60^\circ$ upstream, $12\text{ s}$
D.
$45^\circ$ upstream, $14.14\text{ s}$
Q64
DPT
MCQ
29 Aug 2026
```python
# Let's verify the calculation for the question selected in the AoI:
# "Q. In following figure if man is swimming with velocity $10\text{ m/s}$ wrt river at an angle of $37^\circ$ to the river velocity. Find time taken to cross the river and drift if velocity of river is $10\text{ m/s}$ and width of the river is $30\text{ m}$"
# Let's check the text in the image:
# v_{m/r} = 10 m/s
# angle with river velocity = 37°
# width of river d = 30 m
# river velocity u = 10 m/s
# time to cross: t = d / (v * sin(37°)) = 30 / (10 * sin(37°)) = 30 / (10 * 0.6) = 30 / 6 = 5 sec.
# component of v along river = v * cos(37°) = 10 * 0.8 = 8 m/s
# total velocity along river = u + v * cos(37°) = 10 + 8 = 18 m/s
# drift = (u + v * cos(37°)) * t = 18 * 5 = 90 m.
import math
d = 30
v = 10
u = 10
theta = math.radians(37)
t = d / (v * math.sin(theta))
v_net = u + v * math.cos(theta)
drift = v_net * t
print(f"Time: {t}")
print(f"Drift: {drift}")
```
```text
Time: 4.984920423367449
Drift: 89.66054888228679
```
# Let's verify the calculation for the question selected in the AoI:
# "Q. In following figure if man is swimming with velocity $10\text{ m/s}$ wrt river at an angle of $37^\circ$ to the river velocity. Find time taken to cross the river and drift if velocity of river is $10\text{ m/s}$ and width of the river is $30\text{ m}$"
# Let's check the text in the image:
# v_{m/r} = 10 m/s
# angle with river velocity = 37°
# width of river d = 30 m
# river velocity u = 10 m/s
# time to cross: t = d / (v * sin(37°)) = 30 / (10 * sin(37°)) = 30 / (10 * 0.6) = 30 / 6 = 5 sec.
# component of v along river = v * cos(37°) = 10 * 0.8 = 8 m/s
# total velocity along river = u + v * cos(37°) = 10 + 8 = 18 m/s
# drift = (u + v * cos(37°)) * t = 18 * 5 = 90 m.
import math
d = 30
v = 10
u = 10
theta = math.radians(37)
t = d / (v * math.sin(theta))
v_net = u + v * math.cos(theta)
drift = v_net * t
print(f"Time: {t}")
print(f"Drift: {drift}")
```
```text
Time: 4.984920423367449
Drift: 89.66054888228679
```
Correct Answer:
Q65
DPT
MCQ
29 Aug 2026
Concept:
A.
$4\text{ s}, 80\text{ m}$
B.
$5\text{ s}, 90\text{ m}$
C.
$6\text{ s}, 100\text{ m}$
D.
$5\text{ s}, 75\text{ m}$