iCON Education - Solid State AIIMS Test

iCON Education iconic preparation for JEE and NEET

Font Size

Candidate Name

Student

Exam Name

AIIMS

Test Name

Solid State

Subject

Chemistry

← Back to Solid State

Remaining Time

00:15:00

Question 1: Palette 1/7

AIIMS 2019 MCQ

The tetrahedral voids are present in 0.5 mole of hcp crystal structure

$3.6 \times 10^{23}$

$9 \times 10^{23}$

$3.6 \times 10^{24}$

$6.02 \times 10^{23}$

Question 2: Palette 2/7

AIIMS 2019 MCQ

Which of the following is correct order of packing efficiency?

hcp = fcc > bcc > sc

sc > bcc > hcp = fcc

bcc > sc > hcp < fcc

fcc = hcp > sc > bcc

Question 3: Palette 3/7

AIIMS 2019 MCQ

Assertion : ZnO becomes yellow when it is heated.

Reason : The anionic sites occupied by unpaired electrons (due to F-centres).

If both assertion and reason are true and reason is the correct explanation of assertion.

If both assertion and reason are true, but reason is not the correct explanation of assertion.

If assertion is true, but reason is false.

If both assertion and reason are false.

Question 4: Palette 4/7

AIIMS 2018 MCQ

Which of the following is an example of network solid?

$\mathrm{SO}_2$ (solid)

$\mathrm{I}_2$

Diamond

$\mathrm{H}_2 \mathrm{O}$ (ice)

Question 5: Palette 5/7

AIIMS 2018 MCQ

Niobium crystallises in body centred cubic structure. If density is $8.55 \mathrm{~g} \mathrm{~cm}^{-3}$, then the atomic radius of niobium is (atomic mass of niobium $=93 u$ )

163 pm

143 pm

182 $\mathop A\limits^o $

152 $\mathop A\limits^o $

Question 6: Palette 6/7

AIIMS 2018 MCQ

A solid has a structure in which W atoms are located at the corners of a cubic lattice. O atoms at the centre of edges and Na atom at centre of the cube. The formula for the compound is

$\mathrm{NaWO}_2$

$\mathrm{NaWO}_3$

$\mathrm{Na}_2 \mathrm{WO}_3$

$\mathrm{NaWO}_4$

Question 7: Palette 7/7

AIIMS 2018 MCQ

Assertion (A) Graphite is an example of tetragonal crystal system.

Reason (R) For a tetragonal system, $a=b \neq c$ and $\alpha=\beta=90^{\circ}, \gamma=120^{\circ}$.

Both (A) and (R) are true and (R) is the correct explanation of (A).

Both (A) and (R) are true, but (R) is not the correct explanation of (A).

(A) is true and (R) is false.

Both (A) and (R) are false.

Question Status

Not Visited

Not Answered

Answered

Marked for Review

Question Palette