Let ${f_1}:R \to R,\,{f_2}:\left( { - {\pi \over 2},{\pi \over 2}} \right) \to R,\,{f_3}:( - 1,{e^{\pi /2}} - 2) \to R$ and ${f_4}:R \to R$ be functions defined by
(i) ${f_1}(x) = \sin (\sqrt {1 - {e^{ - {x^2}}}} )$,
(ii) ${f_2}(x) = \left\{ \matrix{
{{|\sin x|} \over {\tan { - ^1}x}}if\,x \ne 0,\,where \hfill \cr
1\,if\,x = 0 \hfill \cr} \right.$
the inverse trigonometric function tan
$-$1x assumes values in $\left( { - {\pi \over 2},{\pi \over 2}} \right)$,
(iii) ${f_3}(x) = [\sin ({\log _e}(x + 2))]$, where for $t \in R,\,[t]$ denotes the greatest integer less than or equal to t,
(iv) ${f_4}(x) = \left\{ \matrix{
{x^2}\sin \left( {{1 \over x}} \right)\,if\,x \ne 0 \hfill \cr
0\,if\,x = 0 \hfill \cr} \right.$
| LIST-I |
LIST-II |
| P. The function $ f_1 $ is |
1. NOT continuous at $ x = 0 $ |
| Q. The function $ f_2 $ is |
2. continuous at $ x = 0 $ and NOT differentiable at $ x = 0 $ |
| R. The function $ f_3 $ is |
3. differentiable at $ x = 0 $ and its derivative is NOT continuous at $ x = 0 $ |
| S. The function $ f_4 $ is |
4. differentiable at $ x = 0 $ and its derivative is continuous at $ x = 0 $ |