Question 1: Palette 1/18

JEE Advanced 2025 MCQ

During sodium nitroprusside test of sulphide ion in an aqueous solution, one of the ligands coordinated to the metal ion is converted to

A

NOS⁻

B

SCN⁻

C

SNO⁻

D

NCS⁻

Question 2: Palette 2/18

JEE Advanced 2025 MCQ

The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

List–I	List–II
(P) Passing $\mathrm{H_2S}$ in the presence of $\mathrm{NH_4OH}$	(1) $\mathrm{Cu^{2+}}$
(Q) $\mathrm{(NH_4)_2CO_3}$ in the presence of $\mathrm{NH_4OH}$	(2) $\mathrm{Al^{3+}}$
(R) $\mathrm{NH_4OH}$ in the presence of $\mathrm{NH_4Cl}$	(3) $\mathrm{Mn^{2+}}$
(S) Passing $\mathrm{H_2S}$ in the presence of dilute $\mathrm{HCl}$	(4) $\mathrm{Ba^{2+}}$
	(5) $\mathrm{Mg^{2+}}$

A

P → 3; Q → 4; R → 2; S → 1

B

P → 4; Q → 2; R → 3; S → 1

C

P → 3; Q → 4; R → 1; S → 5

D

P → 5; Q → 3; R → 2; S → 4

Question 3: Palette 3/18

JEE Advanced 2021 MCQ

Precipitate X is

A

Fe₄[Fe(CN)₆]₃

B

Fe[Fe(CN)₆]

C

K₂Fe[Fe(CN)₆]

D

KFe[Fe(CN)₆]

Question 4: Palette 4/18

JEE Advanced 2021 MCQ

Among the following, the brown ring is due to the formation of

A

[Fe(NO)₂](SO₄)₂]^2$-$

B

[Fe(NO)₂](H₂O)₄]³⁺

C

[Fe(NO)₄](SO₄)₂]

D

[Fe(NO)(H₂O)₅]²⁺

Question 5: Palette 5/18

JEE Advanced 2014 MCQ

M1, Q and R, respectively, are

A

Zn²⁺, KCN and HCl

B

Ni²⁺, HCl and KCN

C

Cd²⁺, KCN and HCl

D

Co²⁺, HCl and KCN

Question 6: Palette 6/18

JEE Advanced 2014 MCQ

Reagent S is

A

K₄[Fe(CN)₆]

B

Na₂HPO₄

C

K₂CrO₄

D

KOH

Question 7: Palette 7/18

JEE Advanced 2013 MCQ

The precipitate P contains

A

Pb²⁺

B

Hg$_2^{2 + }$

C

Ag⁺

D

Hg²⁺

Question 8: Palette 8/18

JEE Advanced 2013 MCQ

The coloured solution S contains

A

$F{e_2}{(S{O_4})_3}$

B

$CuS{O_4}$

C

$ZnS{O_4}$

D

$N{a_2}Cr{O_4}$

Question 9: Palette 9/18

JEE Advanced 2011 MCQ

The metal rod M is

A

Fe

B

Cu

C

Ni

D

Co

Question 10: Palette 10/18

JEE Advanced 2011 MCQ

The compound N is

A

AgNO₃

B

Zn(NO₃)₂

C

Al(NO₃)₃

D

Pb(NO₃)₂

Question 11: Palette 11/18

JEE Advanced 2011 MCQ

The final solution contains :

A

${[Pb{(N{H_3})_4}]^{2 + }}$ and ${[CoC{l_2}]^{2 - }}$

B

${[Al{(N{H_3})_4}]^{3 + }}$ and ${[Cu{(N{H_3})_4}]^{2 + }}$

C

${[Ag{(N{H_3})_2}]^ + }$ and ${[Cu{(N{H_3})_4}]^{2 + }}$

D

${[Ag{(N{H_3})_2}]^ + }$ and ${[Ni{(N{H_3})_6}]^{2 + }}$

Question 12: Palette 12/18

JEE Advanced 2011 MCQ

Passing H₂S gas into a mixture of Mn²⁺, Ni²⁺, Cu²⁺ and Hg²⁺ ions in an acidified aqueous solution precipitates

A

CuS and HgS

B

MnS and CuS

C

MnS and NiS

D

NiS and HgS

Question 13: Palette 13/18

JEE Advanced 2009 MCQ

The compound X is

A

NaNO$_3$

B

NaCl

C

Na$_2$SO$_4$

D

Na$_2$S

Question 14: Palette 14/18

JEE Advanced 2009 MCQ

The compound Y is

A

MgCl$_2$

B

FeCl$_2$

C

FeCl$_3$

D

ZnCl$_2$

Question 15: Palette 15/18

JEE Advanced 2009 MCQ

The compound Z is

A

$M{g_2}[Fe{(CN)_6}]$

B

$Fe[Fe{(CN)_6}]$

C

$F{e_4}{[Fe{(CN)_6}]_3}$

D

${K_2}Z{n_3}{[Fe{(CN)_6}]_2}$

Question 16: Palette 16/18

JEE Advanced 2007 MCQ

A solution of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution. Moreover, the solution of metal ion treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is:

A

Pb$^{2+}$

B

Hg$^{2+}$

C

Cu$^{2+}$

D

Co$^{2+}$

Question 17: Palette 17/18

JEE Advanced 2006 MCQ

A solution when diluted with $\mathrm{H}_2 \mathrm{O}$ and boiled, it gives a white precipitate. On addition of excess $\mathrm{NH}_4 \mathrm{Cl} / \mathrm{NH}_4 \mathrm{OH}$, the volume of precipitate decreases leaving behind a white gelatinous precipitate. Identify the precipitate which dissolves in $\mathrm{NH}_4 \mathrm{OH} / \mathrm{NH}_4 \mathrm{Cl}$.

A

$\mathrm{Zn}(\mathrm{OH})_2$

B

$\mathrm{Al}(\mathrm{OH})_3$

C

$\mathrm{Mg}(\mathrm{OH})_2$

D

$\mathrm{Ca}(\mathrm{OH})_2$

Question 18: Palette 18/18

JEE Advanced 2006 MCQ

$\mathrm{CuSO}_4$ decolourises on addition of KCN , the product is

A

$\left[\mathrm{Cu}(\mathrm{CN})_4\right]^{2-}$

B

$\mathrm{Cu}^{2+}$ get reduced to form $\left[\mathrm{Cu}(\mathrm{CN})_4\right]^{3-}$

C

$\mathrm{Cu}(\mathrm{CN})_2$

D

CuCN