Question 1: Palette 1/8

BITSAT 2025 MCQ

Balance the following redox reaction in acidic medium and determine the stoichiometric coefficient of $\mathrm{H}_2 \mathrm{O}$ in the final balanced equation.

$ \mathrm{MnO}_4^{-}(a q)+\mathrm{Fe}^{2+}(a q) \longrightarrow \mathrm{Mn}^{2+}(a q)+\mathrm{Fe}^{3+}(a q) $

A

2

B

4

C

6

D

8

Question 2: Palette 2/8

BITSAT 2025 MCQ

Calculate the volume of $M / 10 \mathrm{KMnO}_4$ needed to react with 20 mL of $M / 2 \mathrm{FeSO}_4$ in acidic medium.

A

20 mL

B

8.0 mL

C

10.0 mL

D

5.0 mL

Question 3: Palette 3/8

BITSAT 2024 MCQ

What is the stoichiometric coefficient of $ \mathrm{SO}_{2} $ in the following balance reaction?

$ \mathrm{MnO}_{4}^{-}(a q)+\mathrm{SO}_{2}(\mathrm{~g}) \longrightarrow \mathrm{Mn}^{2+}(a q)^{-}+\mathrm{HSO}_{4}^{-}(a q) $

(in acidic solution)

A

5

B

4

C

3

D

2

Question 4: Palette 4/8

BITSAT 2024 MCQ

Volume of $ M / 8 \mathrm{KMnO}_{4} $ solution required to react completely with $ 25.0 \mathrm{~cm}^{3} $ of $ \mathrm{M} / 4 \mathrm{FeSO}_{4} $ in acidic medium is.

A

8.0 mL

B

5.0 mL

C

15.0 mL

D

10.0 mL

Question 5: Palette 5/8

BITSAT 2020 MCQ

How many mL of perhydrol is required to produce sufficient oxygen which can be used to completely convert 2 L of SO₂ gas?

A

10 mL

B

5 mL

C

20 mL

D

30 mL

Question 6: Palette 6/8

BITSAT 2020 MCQ

Choose the correct chemical reaction among the following:

A

CaCN₂ + H₂O $\to$ Ca(OH)₂ + C₂H₂ + NH₃

B

2NH₃ + CaSO₄ + CO₂ + H₂O $\to$ CaCN₂ + (NH₄)₂SO₄

C

CaCl₂ + Na₂SO₄ $\to$ CaSO₄ + 2NaCl

D

CaC₂ + H₂O $\to$ Ca(OH)₂ + 2NaCl

Question 7: Palette 7/8

BITSAT 2020 MCQ

Which of the following reactions represents disproportionation?

A

CrO₅ $\to$ Cr³⁺ + O₂

B

IO$_3^ - $ + I^$-$ + H⁺ $\to$ I₂

C

CrO₂Cl₂ + NaOH $\to$ Na₂CrO₄ + NaCl + H₂O

D

Na₂S₂O₃ + H₂SO₄ $\to$ Na₂SO₄ + SO₂ + S₈ + H₂O

Question 8: Palette 8/8

BITSAT 2020 MCQ

Titration of 0.1467 g of primary standard Na₂C₂O₄ required 28.85 mL of KMnO4

solution. Calculate the molar concentration of KMnO₄ solution.

A

0.01518 M

B

0.001518 M

C

0.15180 M

D

1.5180 M